Question

Water hose has filled up 1/7 of a pool after 1/10 of an hour at this rate how many hours will it take to fill the pool

Answer 1

Given that

time required to filled 1/7 of pool = 1/10

so time required to fill  1 pool = 1/10 ÷ 1/7 = 1/10 × 7 = 7/10 hrs

So 0.7 hrs will require to fill the pool at given rate

Answer 2

Answer:

It takes   $\frac{7}{10}$  of an hour to fill the pool

Step-by-step explanation:

Let x be the number of hours taken to fill the pool.

Using proportion;

1/7 pool=   1/10 hour

1    pool   =   x

cross-multiply

1/7     x   =  1/10

$\frac{x}{7}$   =   $\frac{1}{10}$

cross- multiply

10x = 7

Divide both-side of the equation by 10

$\frac{10x}{10}$      =    $\frac{7}{10}$

(On the left-hand side of the equation 10 at the numerator will cancel-out 10 at the denominaor while at the right-hand side of the equation 7 will be divided by 10)

x =  $\frac{7}{10}$  of an hour

It takes   $\frac{7}{10}$  of an hour to fill the pool