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Troyanec [42]
2 years ago
8

What's that name of the units used for frequency​

Mathematics
2 answers:
damaskus [11]2 years ago
7 0

Answer:

hertz (Hz)

Explanation:

The SI unit for frequency is the hertz (Hz). One hertz is the same as one cycle per second.

Taya2010 [7]2 years ago
3 0

Answer:

The answer is Hertz

Hope it helped!!

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28. What is the maximum number of real roots
attashe74 [19]
The maximum number of real roots is 5 because the degree is 5. The fundamental theorem of algebra states that the degree of a polynomial is the number of real solutions. (The degree is the highest exponent of the polynomial)
6 0
3 years ago
100 more than 146 is
adelina 88 [10]
100 more than 146 is 246
 add 100 to 146 and it becomes 246
6 0
3 years ago
Read 2 more answers
Solve the quadratic equation. (x + 6)2 = 49
kykrilka [37]

Answer:

C

Step-by-step explanation:

To solve, use inverse operations:

(x+6)^2=49\\\sqrt{(x+6)^2} =\sqrt{49} \\x+6=+/-7

Now we solve for both +/- 7.

x+6=7

x=1

x+6=-7

x=-13

3 0
3 years ago
No dia da festança, bianca comprou dos pasteis por $5,20, duas maçãs do amor por $ 3,40 e dois refrigerantes por $7,60. Quanto b
atroni [7]

Responder:

$ 16,2

Explicação passo a passo:

No dia da festa, Bianca comprou os pastéis por US $ 5,20, duas maçãs do amor por US $ 3,40 e dois refrigerantes por US $ 7,60. Quanto bianca você gastou?

O valor gasto por Bianca é a soma de todos os itens que ela comprou:

Pastelaria = $ 5,20

Maçãs do amor = $ 3,40

Refrigerantes = $ 7,60

A soma da soma dá o valor gasto de Bianca:

Doces + Maçãs do Amor + Refrigerante

$ (5,20 + 3,40 + 7,60)

= $ 16,2

5 0
3 years ago
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
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