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2 years ago

Plz helppp meee wallah I swear to god I will mark you as a brainliest and I will give you 20

Mathematics

1 answer:

givi [52]2 years ago

8 0

Answer:

Step-by-step explanation:

Equation for the linear function has been given as,

y = 26 - 4x

For x = 1,

y = 26 - 4(1)

= 26 - 4

= 22

For x = 2,

y = 26 - 4(2)

= 26 - 8

= 18

For x = 3,

y = 26 - 4(3)

= 26 - 12

= 14

For x = 6,

y = 26 - 4(6)

= 26 - 24

= 2

Therefore, table for the function will be,

x y

1 22

2 18

3 14

6 2

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Richard and teo have a combined age of 42. Richard is 9 years older that twice teos age. How old are Richard and Teo

satela [25.4K]

Step-by-step explanation:

Richard and teo age is 51 years old

6 0

3 years ago

At the beginning of an environmental study, a forest covered an area of 1500 km². Since then, this area has decreased by 5.8% ea

Oliga [24]

Area covered by the forest in the beginning = 1500km²

Decrease in area each year = 5.8% = 5.8/100 × 1500 = 87km²

Decrease in the area of the forest in t years = 87t

Area of forest now = y

y = 1500 - 87t

7 0

2 years ago

Write the equation of a line that is perpendicular to x=3x=3x, equals, 3 and that passes through the point (0,-4)(0,−4)left pare

leva [86]

Answer: $x+3y=12$

Step-by-step explanation:

Slope of two lines that are perpendicular to each other is 1.

If one line is $y=3x$ , then its slope = 3 [by comparing to the linear equation y= mx+c, here m=3]

Let n be the slope of the required line, then

$n\times3=-1\\\\\rightarrow\ n=\dfrac{-1}{3}$

Equation of line with slope n and passers through (a,b) is

$(y-b)=n(x-a)$

Equation of line with slope n= $\dfrac{-1}{3}$ and passes through point ( 0,-4) :

$(y-(-4))=\dfrac{-1}{3}(x-0)\\\\\Rightarrow\ y+4=\dfrac{-1}{3}x\\\\\Rightarrow\ -3(y+4)=x\\\\\Rightarrow-3y-12=x\\\\\Rightarrow x+3y=12$

Hence, Required equation : $x+3y=12$

8 0

3 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

Step-by-step explanation:

Denote the events as follows:

D = Dave will show up.

M = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

3 years ago

Read 2 more answers

There are over 2700 species of snakes in the world. OVer 600 species are Venemous. Write the fraction of species that are not ve

Radda [10]

I think it is 600.0027 but I'm not for sure.?

3 0

3 years ago

Read 2 more answers