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denis23 [38]
4 years ago
6

True or false: we can establish causation whenever a random sample is taken.

Mathematics
1 answer:
MakcuM [25]4 years ago
5 0
Causation conclusion can only be made when the experiement is preformed. Due to the potential confounding variables in observational studies which include random samples.
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Can someone help pls!!!
natita [175]
Answer: 42.14 cm^2

square:

Area of a square=s^2
A=14^2
A=196

circle (the two semi circles are the same as one circle):

Area of a circle=(pi)(r)^2

divide 14 (diameter) by 2 to find the radius

A=(3.14)(7)^2
A=(3.14)(49)
A=153.86

subtract the area of the two semi circles from the area of the square to get the answer

196-153.86=42.14
3 0
3 years ago
Determine whether the graph represents a function . If it does represent a function , give its domain and range.
laiz [17]

Answer:

A function is a relationship that maps elements from a set (the domain) into elements from another set (the range)

Such that each element in the domain can be mapped into only one element from the range.

Let's see graphs 18, 20,24 and 30.

Remember that the axis that represents the domain is the horizontal one (usually represented with x), and the vertical axis represents the range (usually represented with y)

18) Here we can see that the point x = 1 his mapped into two different values of y.

we have the pair (1, 2) and the pair (1, -3)

And something similar happens for x = 2.

Then we can conclude that this is not a function.

20) Here we have a linear relationship.

Linear relationships are almost always functions, the only case when these are not functions is when the linear equation is something like x = a.

Linear equations can be written as:

y = a*x + b

So x can be any value, and thus y also can be any value.

Then the domain is the set of all real numbers, and the range is the set of all real numbers.

24) Here we have a quadratic function whose arms go down.

This is a function, now let's see the domain and range.

Quadratic functions are written as:

y = a*x^2 + b*x + c

There is no value of x can cause some problem in this equation, then this function works for all values of x, then the domain is the set of all real numbers.

Now, let's look at the graph.

We can see that the function goes up, reaches a maximum, and then goes down again.

Then the range will be the set of all the values smaller than the maximum we can see in the graph, this is:

y ∈ (-∞, 15]

or simply:

y ≤ 15.

30) Here again, we can see that for x = 0 there are two different values of y.

the same happens for x = -1, x = -2, and a lot of other values.

Then this is not a function, because it is mapping values of the domain into different values of the range.

3 0
3 years ago
A point P is moving along the curve whose equation is y = \sqrt x . Suppose that x is increasing at the rate of 4 units/s when x
Mice21 [21]

Answer:3 units/s

Step-by-step explanation:

Given

y=\sqrt{x}

Point P lie on this curve so any general point on curve can be written as (x,\sqrt{x})

and \frac{\mathrm{d} x}{\mathrm{d} t}=4 units/s

Distance between Point P and (2,0)

P=\sqrt{(x-2)^2+(\sqrt{x}-0)^2}

P at x=3 P=2

rate at which distance is changing is

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{\mathrm{d} \sqrt{(x-2)^2+(\sqrt{x}-0)^2}}{\mathrm{d} t}

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2x-3}{\sqrt{(x-2)^2+(\sqrt{x}-0)^2}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2\times 3-3}{2\times 2}\times 4=3 units/s

8 0
3 years ago
What are the factors of 3x^2 + 23x − 8?
Margaret [11]
<span>3x</span>²<span> + 23x − 8 = 3x</span>² + 24x - x - 8 = 3x(x+8) - (x+8) = (x+8)(3x-1)
8 0
3 years ago
Find the axis of symmetry of the parabola below <br> A-Y=2<br> B-X=2<br> C-X=1<br> D-Y=1
victus00 [196]
The axis of symmetry is given by the line x = a (where a is equivalent to the x-value of the turning point of the parabola) and can be viewed as the line about which the parabola is symmetric; in this case, the parabola has an axis of symmetry of x = 2, thus the answer is B
8 0
3 years ago
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