Let us find the 3 possible
ways to express 3 to the 5th power.
This is an exponential expression.
The first way is => 3 ^ 5
=> in this way, 3 is our base and 5 is our exponent
second way
=> 3 x 3 x
3 x 3 x 3 – In this expression, we multiplied 3 5 times and the
product is 243
Third way
=> 3^2 x 3 ^3
=> we created 2 exponential expression. Bu t the product is still the
same with the other 2
If x = 3 is a solution, (x - 3) is a factor of f(x).
2x³ + x² - 25x + 12 ÷ (x - 3) [by long division] = 2x² + 7x - 4
so f(x) = (x - 3)(2x² + 7x - 4)
f(x) = (x - 3)(2x - 1)(x + 4)
so 'zeros', or more correctly solutions, are: x = 3, x = 1/2 and x = -4.
[by setting each of the factors equal to 0 and solving for x].
I think x is 20 I’m not sure tho since it would come out as -10 instead of positive
The answer is the second one 1/2 -3
