8.4 you hsve to subtract 18-9.6 and you get ur answer. let me know If you need anymore help
If DE and BC are parallel, their sides must be proportional.
2/x+1 = 5/4x-2
Use cross multiplication:
8x-4=5x+5
3x=9
x=3
Plug this in:
x: 3
AE: 3+1 = 4
CE: 4(3)-2 = 12-2 = 10
AB: 2 + 5 = 7
AC: AE+CE = 4 + 10 = 14
Answer:
The answers 50 degrees my guy
Step-by-step explanation:
<span>2y ≥ 3x - 5 = the graph u missed
2y ≤ 3x - 5 = 4th graph
2y < 3x - 5 = 3rd graph
3y ≥ 2x - 5 = 2nd graph
3y < 2x - 5 = 1st graph
3y > 2x - 5 = 5th graph</span>
Answer:
70% (Sorry, had to use the word "com" instead...)
Step-by-step explanation:
The question is asking what percent of students who graduated one of these three schools, graduated from either com laude or magna com laude. You need a total of how many students graduated com laude and how many from magna com laude. 4 graduated from magna com laude, and 10 graduated from com laude. That's 14. Now we need a total of how many students graduated in total. 14 graduated from com laude or magna com laude, and 6 graduated from summa com laude for a total of 20 who graduated. So you just need to do 14 divided by 20, and you'll get the decimal from which you can get a percent. 14 divided by 20 is 0.7. So, that's 70%. 70% of students who graduated, graduated from Magna com laude or Com laude.