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netineya [11]
3 years ago
6

Pierre found a new store where he hopes to save

Mathematics
1 answer:
fgiga [73]3 years ago
5 0
Your first equation is 4x + 7y= 32, the x’s representing the brushes and the y’s the tubes of paint. Our second equation is 6x+8y=43. What I did is I multiplied the first equation by 1.5 so that it turns into 6x+10.5y=48. Then I subtracted the second equation from the first, canceling out the x’s and leaving us with 2.5y=5. Then divided and got y=2. We then go back to any of the original equations and plug it in to get the x’s.
6x+8(2)=43. We get 6x+16=43. We subtract and are left with 6x=27 and then x=4.5. Then plug both of them in to a different equation to double check. You could also use substitution by isolating one of the variables in one equation and then plugging it in to the other one.
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What is 6.62 x 10 ^5 written in standard form?<br> A) 662<br> B) 33.1<br> C) 66,200<br> D) 662,000
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What is the radical form of each of the given expressions?
earnstyle [38]

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6^{\frac{1}{5} }=\sqrt[5]{6}

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Step-by-step explanation:

A radical is the root operation for n roots such as square root or cuberoot in the form \sqrt[n]{x}. A fraction exponent x^{m/n} can be converted to the radical form.

6^{\frac{1}{5} }=\sqrt[5]{6}

6^{\frac{7}{5} }=\sqrt[5]{6^7}

6^{\frac{1}{6} }=\sqrt[6]{6}

7^{\frac{1}{2} }=\sqrt[2]{7}

7^{\frac{5}{2} }=\sqrt[2]{7^5}

6^{\frac{9}{2} }=\sqrt[2]{6^9}

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