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antoniya [11.8K]
3 years ago
10

Solve for x: m(fx+a)=z+g

Mathematics
2 answers:
goblinko [34]3 years ago
8 0
First you need to divide m over to get fx+a=(z+g)/m
Then you subtract a on both sides to get fx=((z+g)/m)-a
Next you divide f on both sides to get x=((f(z+g)/m)-(a/f) which is your awnser.
Inga [223]3 years ago
4 0
X= -a/f = z/mf + g/mf
-a is over f
+ z over mf
+ g over mf
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Solve the equation for x. the square root of the quantity x plus 4 end quantity minus 7 equals 1
HACTEHA [7]

Answer:

<h2>x = 60</h2>

Step-by-step explanation:

I hope it helps :)

\sqrt{x+4} -7=1\\\mathrm{Add\:}7\mathrm{\:to\:both\:sides}\\\sqrt{x+4}-7+7=1+7\\\sqrt{x+4}=8\\\mathrm{Square\:both\:sides}\\\left(\sqrt{x+4}\right)^2=8^2\\x+4=64\\x = 64-4\\x = 60

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3 years ago
Part A: Find the LCM of 5 and 12. Show your work. (3 points)
diamong [38]

Answer:

Part A: 60

5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60.

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Part B: 9

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Part C: 9 (8 + 9)

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GCF of 72 and 81 is 9...

Divide 72 by 9 and get 8.

Divide 81 by 9 and get 9.

To check multiply 9 with 8, and multiply 9 by 9.

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3 years ago
A ball is thrown at a 30 degree angle above the horizontal with a speed of 10 ft/s. After 0.50s the horizontal component of it's
mezya [45]
<span>A ball is thrown at a 30 degree angle above the horizontal with a speed of 10 ft/s. After 0.50s the horizontal component of it's velocity will be the same. In a projectile motion the horizontal component of the velocity is said to be constant. Therefore, it will be equal to the initial velocity.</span>
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Gnoma [55]
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Yakvenalex [24]

Answer:

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Step-by-step explanation:

Dont know if thats o or and zero but I solve it by using o..if it was a zero then comment that so I can redo it anyways heres the explanation

(7nm^5 o^2) × (-3m^3 o^5)^2

7m^5 no^2) ×(-3m^3 o^5) ^2

(7m^5 no^2) × (3m^3 o^5)^2

7m^5 no^2 × (3m^3 o^5) ^2

7m^5 no^2 × 9m^6 o^10

63m^11 no^12

3 0
3 years ago
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