Answer:
(4) 5 m
Step-by-step explanation:
You want the length of side x of a right triangular prism with base edge lengths of 2.5 m and 2 m, and a volume of 12.5 m³.
<h3>Volume</h3>
The volume of the prism is given by the formula ...
V = Bh
where B is the area of the base:
B = 1/2bh . . . . where b and h are the leg dimensions of the right triangle
Using these formulas together, we have ...
V = 1/2(2.5 m)(2 m)x
12.5 m³ = 2.5x m²
Dividing by 2.5 m², we find x to be ...
(12.5 m³)/(2.5 m²) = x = 5 m
The dimension labeled x has length 5 meters.
Answer:
Building linear equations for f and g, it is found that the y-intercept of (f - g)(x) is of y = 8.------------A linear function has the following format:[tex]y ...
Step-by-step explanation:Use the two points to compute the slope, m, then use one of the points in the form y=m(x)+b to find the value of b.
Given:
To find:
The product of the polynomials.
Solution:
1. 
Multiply the numerical coefficient and add the powers of x.
2. 
Multiply each term of first polynomial with each term of 2nd polynomial.
Multiply the numerical coefficient and add the powers of x.
3. 
Multiply each term of first polynomial with each term of 2nd polynomial.
Multiply the numerical coefficient and add the powers of x.
Add or subtract like terms together.
The answer for multiplying polynomials:
Answer:
UNIF(2.66,3.33) minutes for all customer types.
Step-by-step explanation:
In the problem above, it was stated that the office arranged its customers into different sections to ensure optimum performance and minimize workload. Furthermore, there was a service time of UNIF(8,10) minutes for everyone. Since there are only three different types of customers, the service time can be estimated as UNIF(8/3,10/3) minutes = UNIF(2.66,3.33) minutes.
Answer:
U ={ Parallelograms}
A= { Parallelogram with four congruent sides}={ Rhombus,Square}
B ={ Parallelograms with four congruent angles} ={ Rectangle, Square}
So, AB= { Square}
So among all the parallelograms "Square" is the only parallelogram which has all congruent sides as well as all congruent angles.
