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Scrat [10]
3 years ago
7

5th grade math. correct answer will be marked brainliest.

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

1 7/30

Step-by-step explanation:

3 - (1 1/6 + 3/5) =

3 - (1 5/30 + 18/30) =

3 - 1 23/30 =

1 7/30

<em>Hope that helps!</em>

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The perpendicular bisector of the line segment connecting the points $(-3,8)$ and $(-5,4)$ has an equation of the form $y = mx +
docker41 [41]

Answer:

m = -1/2 and b = 6.5

Step-by-step explanation:

To find the slope of the original line segment, we have to do the change in y/the change in x:

(4-8)/(-5--3) = -4/-2 = 2

2 is the slope of the original line segment, but since this is the perpendicular bisector, we have to take the negative reciprocal of 2 so m = -1/2

To find b we substitute the values of x, y, and m into the equation. Let's use the x value of -3 and the y value of 8:

y = mx + b

8 = -1/2(-3) + b

8 = 3/2 + b

6.5 = b

5 0
3 years ago
Pls I need help with this
LiRa [457]

Answer:

third side = 4

Step-by-step explanation:

third side is hypoenuse as it is opposite to 90 degree.

using pythagoras theorem

(perpendicular)^2 + (base)^2 = (hypotenuse)^2

2^2 + (2\sqrt{3 )^2 = hypotenuse^2

4 + 4*3 = hypotenuse^2

16 = hypotenuse^2

\sqrt{16} = hypotenuse

4 = hypotensue

7 0
3 years ago
Rashal is adding the expression below. Negative 3 + left-bracket (negative 7) + (negative 6) right-bracket First, he rewrites th
diamong [38]
I think it is 3 I think I’m not sure
6 0
3 years ago
Read 2 more answers
Use (&lt;, &gt;, =) to compare 2⁄3 and 3⁄4. A. None of the above B. 2⁄3 &gt; 3⁄4 C. 2⁄3 &lt; 3⁄4 D. 2⁄3 = 3⁄4
Vinvika [58]
C 3/4 >2/3 bc 3/4=.75 and 2/3 = .66
4 0
3 years ago
We have a right triangle that has am 8 meter and 21 meter leg .Find the hypotenuse
Serjik [45]

Answer:

hypotenuse is 22.47 m

Step-by-step explanation:

The length of both legs of a right angle triangle are 8m and 21 m

We need to find the hypotenuse

To find hypotenuse we use Pythagorean theorem

Hypotenuse is AC  and other two legs are AB  and BC

AC^2 = AB^2 + BC^2

Hypotenuse ^2 = 8^2 + 21^2

hypotenuse = \sqrt{8^2 + 21^2}

= \sqrt{64 + 441}

= \sqrt{505}

= 22.47

So the length of the hypotenuse is 22.47 m

4 0
3 years ago
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