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3 years ago

8

In 2010 the estimated population was 2.7 times 10 to the 6 people. That population of Illinois that same year was about 4.76 tim

es this number

1 answer:

Keith_Richards [23]3 years ago

8 0

that would be just multipacation

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Write five next terms:0;1;1;2;3;5;8;13

Iteru [2.4K]

Answer:

it's a(n)=a(n-1)+a(n-2)

this is also known as Fibonacci sequence

0

1

1

2

3

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8

13

21

34

55

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7 0

2 years ago

A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Houston. The stud

iris [78.8K]

Answer:

$-0.048$

Do not reject $H_0:P_1-P_2=0$

Step-by-step explanation:

From the question we are told that

Sample size $n_1=350$

Sample size $n_2=250$

Sample proportion 1 $\hat P= \frac{25}{350} =>0.07$

Sample proportion 2 $\hat P= \frac{19}{250} =>0.076$

95% confidence interval

Generally for 95% confidence level

Level of significance

$\alpha = 1-0.95=>0.05$

$\alpha /2=\frac{0.05}{2} =>0.025$

Therefore

$Z_a_/_2=1.96$

Generally the equation for confidence interval between $P_1 - P_2$ is mathematically given as

$(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2} }$

$(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250} }$

$(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4 }$

$(-0.006)\pm 0.042$

$(-0.006)- 0.042=>-0.048$

$(-0.006)+ 0.042=>0.036$

Therefore

Confidence interval is

$-0.048$

Conclusion

Given the confidence interval has zero

Therefore do not reject $H_0:P_1-P_2=0$

6 0

2 years ago

What is the simplest for of 72

White raven [17]

Answer:

18/25

Step-by-step explanation:

And as any numbers can divide exactly both numbers, then “18/25” is the simplest form of “. 72”.

8 0

3 years ago

Read 2 more answers

The heights of North American women are normally distributed with a mean of 64 inches and a standard deviation of 2inches.a. Wha

Charra [1.4K]

Answer:

a) $P(X>66)=P(Z>1)=1-P(Z$

b) $P(\bar X >66)=P(Z>2)=1-P(Z$

c) $P(\bar X >66)=P(Z>10)=1-P(Z$

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(64,2)$

Where $\mu=64$ and $\sigma=2$

We are interested on this probability

$P(X>66)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-\mu}{\sigma})=P(Z>\frac{66-64}{2})=P(Z>1)$

And we can find this probability on this way:

$P(Z>1)=1-P(Z$

3) Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{4}}}=2)$

And using a calculator, excel or the normal standard table we have that:

$P(Z>2)=1-P(Z$

4) Part c

$P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{100}}}=10)$

And using a calculator, excel or the normal standard table we have that:

$P(Z>10)=1-P(Z$

3 0

3 years ago

Choose the answer that best represents the situation described below. George is climbing a mountain. He knows that the higher th

alex41 [277]

It’s c the time to climb in the function of its height

3 0

2 years ago