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erastovalidia [21]
2 years ago
14

Need help for test asap!

Mathematics
1 answer:
klio [65]2 years ago
3 0

Answer:

do the test then

Step-by-step explanation:

do the test then

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What coordinate changes when reflected over the y-axis?
Alexeev081 [22]

Answer:

When a point is reflected across the y-axis, the y-coordinate(s) remain the same. But the x-coordinate(s) is transformed into opposite signs.

7 0
2 years ago
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What is the length of the hypotenuse of the triangle?
atroni [7]

Step-by-step explanation:

Hey there!

Here;

ABC is a Right angled triangle.

Taking reference angle as angleA.

Now;

Hypotenuse (h) = AB

Perpendicular (BC)= 24 ft.

Base(AC)= 10 ft.

Now, Using Pythagoras relation;

h =  \sqrt{ {p}^{2}  +  {b}^{2} }

Put all values.

h =  \sqrt{ {24}^{2}  +  {10}^{2} }

Simplify it.

h =  \sqrt{576 + 100}

h =  \sqrt{676}

Therefore, h= 26ft.

<u>ANS</u><u>:</u><u> </u><u>OPTIO</u><u>N</u><u> </u><u>A</u><u>.</u>

<em><u>Hop</u></em><em><u>e</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
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If the measure of angle A is 27 degrees, what is the measure of angle 'B'?
timama [110]

Answer:

i'm pretty sure that it is 27 due to vertical angle theorem

let me know if its right :)

Step-by-step explanation:

4 0
2 years ago
What is the interquartile range of the data set?
anastassius [24]

The interquartile range of the data set will be 30.

<u><em>Explanation</em></u>

Given data set: { 40, 48, 62, 60, 62, 40, 25, 50, 20, 30, 55 }

First we will rearrange the data in numeric order. So...

{ 20, 25, <u><em>30</em></u>, 40, 40, 48, 50, 55, <u><em>60</em></u>, 62, 62 }

Here the middle value in the set is 48. So, the median is 48 and it is diving the whole set into two different data sets. The median of the first set is 30 and median of the second set is 60.

That means, Lower quartile(Q₁) = 30 and Upper quartile(Q₃) = 60

So, the interquartile range of the data set: IQR= Q₃ - Q₁ = 60 - 30 = 30




6 0
3 years ago
Delicious Candy markets a two-pound box of assorted chocolates. Because of imperfections in the candy making equipment, the actu
nikitadnepr [17]

Answer:

a. f(x)= 1.25\ \ \ \ , \  for \ 31.8\leq x\leq 32.6

b. \ P(X=32)=0\\P(X>32.3)=0.375\\P(X

c. No.  Delicious Candy isn't violating any government regulations

Step-by-step explanation:

a.

-A uniform distribution is given by the formula:

f(x)=\frac{1}{b-a} \ \ \ for \ \ \ a\leq x\leq b

#we substitute our values in the formula above to determine the distribution:

f(x)=\frac{1}{b-a}\\\\=\frac{1}{32.6-31.8}\\\\=1.25\\\\\therefore f(x)=1.25, \ \ \ 31.8\leq x\leq 32.6

Hence, the probability density function for the box's weight is given as: f(x)=1.25, \ \ \ 31.8\leq x\leq 32.6

b. The probability of the box's weight being exactly 32 ounces is obtained by integrating f(x) over a=b=32:

f(x)=1.25, \ \ \ a\leq x\leq b\\\\=\int\limits^{32}_{32} {1.25} \, dx \\\\\\=[1.25x]\limits^{32}_{32}\\\\\\=1.25[32.0-32.0]\\\\\\=0

Hence,  the probability that a box weighs exactly 32 ounces is 0.000

ii.The probability that a box weighs more than 32.3 is obtained by integrating f(x) over the limits 32.3 to 32.6 :

f(x)=1.25, \ \ \ a\leq x\leq b\\\\=\int\limits^{32.6}_{32.3} {1.25} \, dx \\\\\\=[1.25x]\limits^{32.6}_{32.3}\\\\\\=1.25[32.6-32.3]\\\\\\=0.375

Hence, the probability that a box weighs more than 32.3 ounces is 0.3750

iii. The probability that a box weighs less than 31.8 is 0.000 since the weight limits are 31.8\leq x\leq 32.6.

-Any value above or below these limits have a probability of 0.000

c. Let 32 ounces be the government's stated weight.

1.25(32.6-32)=0.75\\\\0.75>0.60

Hence, Delicious Candy isn't violating any government's regulations.

8 0
3 years ago
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