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ANTONII [103]
3 years ago
9

The graph of a logarithmic function is shown below.

Mathematics
1 answer:
raketka [301]3 years ago
3 0
Not 100% but all real number so D
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. (a + b)2 – (2a – b)
inn [45]

Answer:

(-b) is the answer.

Step-by-step explanation:

2(a-b)-(2a-b)

=2a-2b-2a+b (opening the brackets)

= -b

Hope this helps you buddy. Have a nice day^_^.

If you have doubt then you can ask in comments. I will surely answer.

3 0
3 years ago
Read 2 more answers
X2-5x+10=0 is it quadratic equation? how can i identify the value of a,b,c? help
natali 33 [55]
A= 1
B= -5
C= 10

In order to figure it out, you can think about it like this..

4 0
3 years ago
F(x)=4x2+6 what is the answer
Tanya [424]
The answer is 14 even
3 0
3 years ago
Help please!!!!!!!!!!!!! Explain if possible
iris [78.8K]
Answer is C.
For every option, sub in the value and find the answer that matches the equation!

Example for option A, F(x) = x + 4 and G(x) = x²
G(F(x)) = G(x + 4) ーー> sub in the value of F(x)
Let's take the subbed in value, (x + 4) as x, and this x will be the x for G(x).

∴ Since G(x) is x²
G(x + 4) = (x + 4)² ーー> remember (x + 4) is represented as x.
= x² + 16
∴ You know that the answer is not A, do this for all options and you'll find the answer, C!

4 0
3 years ago
The length (in centimeters) of a typical Pacific halibut t years old is approximately f(t) = 200(1 − 0.956e−0.18t). Suppose a Pa
horsena [70]

Answer:

7.2 years

Step-by-step explanation:

f(t) =200(1 - 0.956e^{-0.18t})

where f(t) is the length and t is the number of years old

given the Mike measures 148 cm, we need to find out the age

So we plug in 148 for f(t) and solve for t

148 =200(1 - 0.956e^{-0.18t})

divide both sides by 200

\frac{148}{200} = 1 - 0.956e^{-0.18t}

Now subtract 1 from both sides

-0.26= - 0.956e^{-0.18t}

Divide both sides by -0.956

\frac{0.26}{0.956} =e^{-0.18t}

Now take ln on both sides

\frac{0.26}{0.956} =e^{-0.18t}

ln(\frac{0.26}{0.956} )=-0.18tln(e)

ln(\frac{0.26}{0.956} )=-0.18t

divide both sides by -0.18

t=7.2

So 7.2 years

5 0
3 years ago
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