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otez555 [7]
3 years ago
12

Question 4

Mathematics
1 answer:
alex41 [277]3 years ago
8 0

Answer:

Step-by-step explanation:

O

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Can y’all also show me how to do this so I won’t have to come back here for help plz
Igoryamba

Answer:

the value of x = 56

Step-by-step explanation:

if both are similar figures, then ratio of their

sides will be constant , so

=》14 / 17 = x / 68

=》14 / 17 × 68 = x

=》14 × 4 = x

=》x = 56

hence, value of x = 56.

i hope you got it.

8 0
3 years ago
Can someone help me
marshall27 [118]

Answer:

16682.7 cm³

Step-by-step explanation:

The total volume is the volume of the cone plus half the volume of a sphere:

V = ⅓ π r² h + ½ (4/3 π r³)

V = ⅓ π r² h + ⅔ π r³

V = ⅓ π r² (h + 2r)

Given that r = 4.15 cm and h = 10.2 cm:

V = ⅓ π (4.15)² (10.2 + 2×4.15)

V ≈ 333.65

The volume needed for 50 cones is therefore:

50V ≈ 16682.7 cm³

7 0
4 years ago
What is the unit rate for $4.75
Softa [21]

Answer:

2.436

Step-by-step explanation:

It’s Right Trust me

4 0
3 years ago
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
3 years ago
Write a polynomial equation of degree 4 that has the following roots : -1 repeated three times and 4
Radda [10]

Answer:

x^4 -x^3 -9x^2 -11x -4

Step-by-step explanation:

We can use the zero product property

(x-a)  (x-b) (x-c) (x-d)  where a b c d are the roots

(x- -1)(x- -1)(x- -1) ( x-4) since the root -1 is repeated 3 times and 4 is a root

(x+1)(x+1)(x+1) ( x-4)

Foil the first two terms  and the last two terms

(x^2 + 2x+1)( x^2 -3x-4)

Foil again

x^4 -3x^3 -4x^2 +2x^3 -6x^2 -8x +x^2 -3x-4

Combine like terms

x^4 -x^3 -9x^2 -11x -4

6 0
4 years ago
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