All categories

2 years ago

Help Please!!!!!!!!!!! Questions 9 and 10

Mathematics

1 answer:

Sphinxa [80]2 years ago

3 0

Answer:

Step-by-step explanation:

1. ∠ACB ≅∠ECD ; vertical angles are congruent (A)

2. C is midpoint of AE ; given

3. AC ≅CE; midpoint divides the line segment in 2 congruent segments (S)

4.AB║DE; given

5. ∠A≅∠E; alternate interior angles are congruent (A)

6. ΔABC≅ΔEDC; Angle-Side-Angle congruency theorem

1. YX≅ZX; given (S)

2. WX bisects ∠YXZ; given

3. ∠YXW≅∠ZXW; definition of angle bisectors (A)

4. WX ≅WX; reflexive propriety(S)

5. ΔWYX≅ΔWZX; Side-Angle-Side theorem

You might be interested in

Solve.<br><br> 6 divided by 2(1 + 2) =<br><br> Ok goodluck please tell me the answer :)

dalvyx [7]

Answer:

Step-by-step explanation:

Based on the order of operations, this would be 3 times 3, which is 9 I think.

4 0

3 years ago

Read 2 more answers

What number is at this position ?

Katarina [22]

The answer is 2.5 because the point is at the middle. Hope this’ll help

8 0

2 years ago

A study finds that 80% of the local high school students text while doing homework. Ten students are selected at random from the

AysviL [449]

Answer:

Step-by-step explanation:

6 0

2 years ago

State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

7 0

2 years ago

S_A_V [24]

The corect answer for this question

6 0

2 years ago