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3 years ago

find the slope intercept form of the equation of the the line that passes through (-9,-8) and the origin

2 answers:

8 0

Answer: y=8/9x+0

Step 1: Determine the 2 points that will be used

(-9,-8)
(0,0)

Step 2: Starting with finding slope, write out the equation that you need to use

y2-y1/x2-x1

Step 3: Substitute the points into the equation and solve

0- -8/ 0- -9 = 8/9

*This will be the slope*

Step 4: Write out the equation in slope-intercept form

y= 8/9x+b

Step 4: To find the y-intercept, substitute y and x from a point and solve

y=8/9x+b

-8= 8/9 (-9) +b

-8= -8 +b
+8 +8
_______
0=b

*This will be the y-intercept*

Step 5: Replace b and m in the equation to get your final answer

y=mx+b

y=8/9x+0

Hope this helps comment below for more questions :)

Debora [2.8K]3 years ago

5 0

Answer:

The answer is y=8/9x

Step-by-step explanation:

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Hey!

To solve x in this equation we must first add five to both sides to get $\sqrt{x}$ on its own.

Original Equation :
$\sqrt{x} - 5 = x - 11$

New Equation {Added 5 to Both Sides} :
$\sqrt{x} =x-6$

Now we must square both sides of the equation.

Old Equation :
$\sqrt{x} =x-6$

New Equation {Changed by Squaring Both Sides} :
$x= x^{2} -12x+36$

And now we must solve the new equation.

Step 1 - Switch sides
$x^{2} -12x+36=x$

Step 2 - Subtract x from both sides
$x^{2} -12x+36-x=x-x$

Step 3 - Simplify
$x^{2} -13x+36=0$

Now we need to solve the rest of the equation using the quadratic formula.

$\frac{-(-13)+ \sqrt{(-13) ^{2}-4*1*36 } }{2*1}$

${13+ \sqrt{(-13)^{2}-4*1*36 }=13+ \sqrt{25}$

$\frac{13+ \sqrt{25}}{2}$

$\sqrt{25}=5$

$\frac{13+5}{2}$

$\frac{18}{2}$

9

$\frac{-(-13)- \sqrt{(-13) ^{2} -4*1*36} }{2*1}$

4

So, this means that in the equation $\sqrt{x} -5=x-11$ , x = 9 and x = 4.

Hope this helps!

- Lindsey Frazier ♥

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