Speed (S) = Distance (D) / time (t)
First stretch
45 = D / 2
D = 45*2
D = 90 mp
How is the same distance:
Second stretch
S = 90 / t
Average speed (AS):
AS = (S1+S2) / 2
60 = [45+(90/t)] / 2
120 = 45+90/t
120-45 = 90/t
75 = 90/t
t = 90/75
t = 1,2 h
________________________
And now:
S = 90 / t
S = 90 / 1,2
S = 75 mph
Answer:
293.38 pounds
Step-by-step explanation:
We are given that
Distance between poles=35 feet

Weight of cable=10.4 per linear foot
We have to find the weight of the cable.
Differentiate w.r.t




Let 


![s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B2%7D%7B0.0225%7D%5Ctimes%5Cfrac%7B2%7D%7B3%7D%5Bt%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5D%5E%7B17.5%7D_%7B0%7D)
![s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D2%5Ctimes%20%5Cfrac%7B2%7D%7B3%5Ctimes0.0225%7D%5B%281%2B0.0255x%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%5D%5E%7B17.5%7D_%7B0%7D)

s=28.21
Weight of cable=
pound
Answer: (13, -8)
Step-by-step explanation:
Subtract 5 from -3
Add 5 to 8
Answer: y=7/5-9x/5
Step-by-step explanation:
im sorry if this dont help
that is not a function, because there are two outputs for three. two inputs can have one output, but one input cant have two outputs.