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lina2011 [118]
3 years ago
7

In ΔOPQ, q = 6.5 inches, o = 8.6 inches and ∠P=55°. Find ∠Q, to the nearest 10th of an degree.

Mathematics
2 answers:
Nikitich [7]3 years ago
8 0

Answer:

∠Q = 35.5°

Step-by-step explanation:

We are given;

q = 6.5 inches

o = 8.6 inches

∠P = 55°

Let's first use cosine rule to find p.

p² = q² + o² - 2qo cos P

Plugging in the relevant values;

p² = 6.5² + 8.6² - (2 × 6.5 × 8.6 × cos 55)

p² = 42.25 + 73.96 - 32.0629

p² = 84.1471

p = √84.1471

p = 9.17 inches

Using sine rule, we can find ∠Q;

p/sin P = q/sin Q

sin Q = (q•sinP)/p

sin Q = (6.5 × sin 55)/9.17

sin Q = 0.5806

Q = sin^(-1) 0.5806

Q ≈ 35.5°

Vlad1618 [11]3 years ago
3 0

Answer:

47.5  

Step-by-step explanation:

From delta math

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1.11 x 10^-5 standard form
zavuch27 [327]

Answer:

.0000111

Step-by-step explanation:

move the decimal five places to the left because the 5 is negative

8 0
3 years ago
(3x+2)∧2=9 how do i solve this in the square root property
Irina18 [472]
(3x+2)^2=9 \\\\9x^2+12x+4-9=0\\\\9x^2+12x-5=0\\\\a=9,\ \ b=12, \ \ c=-5

x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-12-\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12-\sqrt{144+180}}{18}=\\\\=\frac{-12-\sqrt{324}}{18}=\frac{-12-18}{18}=\frac{-30}{18}=-\frac{5}{3}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-12+\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12+18}{18}=\frac{6}{18}=\frac{1}{3} \\\\Answer: \ x=-\frac{5}{3}\ \ and \ \ x=\frac{1}{3}
 

6 0
3 years ago
Show how to use substitution or elimination to solve the following system of equations. Write the solution as an ordered pair.
max2010maxim [7]

Answer:

  (4, 6)

Step-by-step explanation:

<u>Substitution</u>

Using the second equation, we can substitute for y in the first equation.

  4x -(2x-2) = 10

  2x +2 = 10 . . . . simplify

  x +1 = 5 . . . . . . .divide by 2

  x = 4 . . . . . . . . . subtract 1

  y = 2(4) -2) = 6 . . . . substitute for x in the equation for y

The solution is (x, y) = (4, 6).

__

<u>Elimination</u>

Often, we like to start with both equations in standard form when we solve by elimination. That is nice, but not completely necessary.

We can eliminate the y-variable by simply adding the two given equations.

  (4x -y) +(y) = (10) +(2x -2)

  4x = 8 + 2x . . . . . collect terms. The y-variable has been eliminated.

  2x = 8 . . . . . . . . . subtract 2x

  x = 4 . . . . . . . . . . divide by 2

Y can be found using the second equation.

  (x, y) = (4, 6)

__

We could have eliminated the x-variable by multiplying the second equation by 2, then adding the two equations.

  (4x -y) +2(y) = (10) +2(2x -2)

  y = 6 . . . . . . . . . subtract 4x from both sides. The x-variable has been eliminated.

Now, x can be found using either equation.

  6 = 2x -2 . . . substitute for y in the second equation

  3 = x - 1 . . . divide by 2

  x = 4 . . . . . add 1

  (x, y) = (4, 6)

3 0
3 years ago
PLEASE HELP WILL GIVE BRAILEST TO CORRECT ANSWER!!!!
larisa86 [58]

Answer:

opps type miss

Step-by-step explanation:

miss type

3 0
3 years ago
Select the equations of the lines that are parallel to the line whose equation is y = 3x + 5. There might be more than one answe
o-na [289]
Parallel means they have the same slope.
The given equation has a slope of 3. Slope intercept equation: y = mx + b
a. 6x + 2y = 12
Subtract 6x from both sides.
2y = - 6x + 12
Divide both sides by 2.
y = -3x + 6 Not parallel

b. -3x + y = 8
Add 3x to both sides.
y = 3x + 8 Parallel

c. 3y = 9x
Divide both sides by 3
y = 3x Parallel

d. y = -1/3x Not parallel

B and C are parallel
6 0
3 years ago
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