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Anika [276]
3 years ago
8

PLEASE HELP ME PLEASE PLEASE

Mathematics
1 answer:
Shtirlitz [24]3 years ago
5 0

Answer:

8/2

Step-by-step explanation:

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3 years ago
A committee of 5 people is to be chosen from a group of 8 women and 10 men. How many diffferent committees are possible? How man
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A) 5 to be chosen among a Total : 10 Men + 8 Women

¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five

b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
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Groups of 5 with only women: ⁸C₅ = 56

So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees 

c) 3 Women and 2 Men:

⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M

d) More women than men, it means:
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  4 W + 1 M OR   ⁸C₄ x ¹⁰C₁   →→→→ =    700
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Total where W>M = 3,276 groups of 5 where women are at least 3


3 0
3 years ago
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