Answer:
5
Step-by-step explanation:
Answer:
3 patients had all the three complaints
Step-by-step explanation:
Let U be the set of patients who reported at the hospital on that day
Let F be the set of patients who complained of fever
Let S be the set of patients who had stomach troubles
Let I be the set of injured patients
Then the given data can be written as:
- n(U) = n(F∪S∪I) = 100
- n(F) = 70
- n(S) = 50
- n(I) = 30
- n(F∩S) + n(S∩I) + n(I∩F) - 3×n(F∩S∩I) = 44
n(F∩S∩I) = ?
Using the formula for the cardinal number of union of three sets:
n(F∪S∪I) = n(F) + n(S) + n(I) - n(F∩S) - n(S∩I) - n(I∩F) + n(F∩S∩I)
100 = 70 + 50 + 30 - (44 + 3×n(F∩S∩I)) + n(F∩S∩I)
100 = 150 - 44 - 2×n(F∩S∩I)
2×n(F∩S∩I) = 106 - 100 = 6
<u>n(F∩S∩I) = 3</u>
Answer:
The answer to this question can be defined as follows:
Step-by-step explanation:
In the question some iformation is missing, which can be defined as follows:
Given:
The value of males:
The value of Females:
Calculating Degrees of Freedom:
for 95% confidence interval are:
From its t-distribution table , the value of t has an region of () for (df=95) in its upper tail.
shall be given by = t {0.025}=1.985
Calculating the margin of Error:
The difference in mean bill color "" with 95% confidence intervals:
Lower limit=3.771
Upper limit = 5.249
Answer:
y = (1/4)(x - 6)² + 8
Step-by-step explanation:
x² - 4y - 12x + 68 = 0
put in standard form
-4y = -x² + 12x - 68
4y = x² - 12x + 68
y = (1/4)(x² - 12x + 68)
use 1/2 the x coefficent, (-12/2 = -6), as the complete the square term
y = (1/4)(x - 6)² + 68/4 - (1/4)(-6)²
y = (1/4)(x - 6)² + 17 -9
y = (1/4)(x - 6)² + 8
Answer:
A cube with sides of 5 cm holds 5 layers of 25 cm cubes.
A cube with sides of 10 cm could hold 10 layers of 100 cm cubes.
Step-by-step explanation:
For Cube a
Edge length = 10cm
Hence,
Volume = (side length)³
Volume = (10cm)³
= 1000cm³
For cube b
Side/Edge length = 5cm
Volume of cube = (5 cm)³
= 125 cm³
Gerardo statement is wrong.
Therefore, the correct explanation is given as:
A cube with sides of 5 cm holds 5 layers of 25 cm cubes.
A cube with sides of 10 cm could hold 10 layers of 100 cm cubes.