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alina1380 [7]
3 years ago
6

Please answer both or ill have to report you. Thanks

Mathematics
1 answer:
vaieri [72.5K]3 years ago
5 0
The first one is a and the second one is a
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8 0
4 years ago
1) Se o 5o e o 9-o termos de uma PA são, respectivamente, 40 e 68, então a razão r da progressão é: a) r = 6 b) r = 7 c) r = 9 d
Maslowich

Answer:

1) b) r = 7

2) e) 82

Step-by-step explanation:

Progressão aritmética:

Em uma progressão aritmética, a diferença entre termos consecutivos é sempre a mesma, chamada de razão.

O n-ésimo termo de uma PA é dado por, tomando o primeiro termo como referência:

a_n = a_1 + (n-1)r

Tomando o m-ésimo termo como referência, tem-se que:

a_n = a_m + (n-m)r

1) Se o 5o e o 9-o termos de uma PA são, respectivamente, 40 e 68, então a razão r da progressão é:

a_5 = 40, a_9 = 68. Então:

a_n = a_m + (n-m)r

68 = 40 + 4r

4r = 28

r = \frac{28}{4} = 7

Então a resposta correta é dada pela alternativa b.

2) Inserindo-se 6 números entre 72 e 107, de modo que a sequência (72, a2, a3, a4, a5, a6, a7 ,107) seja uma progressão aritmética, tem-se a3 igual a:

O primeiro termo é a_1 = 72 e o oitavo termo é a_8 = 107. Com isso, é possível encontrar a razão.

a_n = a_1 + (n-1)r

107 = 72 + 7r

7r = 35

r = \frac{35}{7} = 5

Então, o terceiro termo é:

a_3 = a_1 + 2r = 72 + 2(5) = 82

Logo, a resposta correta é dada pela alternativa e.

5 0
3 years ago
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