Answer:
Please find attached a drawing of the triangles ΔRST and EFG showing the angles
The angle on ΔEFG that would prove the triangles are similar is ∠F = 25°
Step-by-step explanation:
In order to prove that two triangles are similar, two known angles of each the triangles need to be shown to be equal
Given that triangle ∠R and ∠S of triangle ΔRST are 95° and 25°, respectively, and that ∠E of ΔEFG is given as 90°, then the corresponding angle on ΔEFG to angle ∠S = 25° which is ∠F should also be 25°
Therefore, the angle on ΔEFG that would prove the triangles are similar is ∠F = 25°.
Step-by-step explanation:
C= 72..............
C3=216
C=216
3
C = 72
Thanks
Answer:
-87 (If I'm correct - sorry if I'm not)
Step-by-step explanation:
<u>substitute:</u>
4(3-6) - 3(-5)^2
<u>Parenthesize:</u>
4(-3) - 3(-5)^2
<u>Exponents:</u>
4(-3) - 3(25)
<u>Multiply:</u>
-12 - 75
<u>Subtract:</u>
-12 - 75 = -87
<u>ANSWER::::</u>
<u><em>-87</em></u>
The slope is -2:) hope this helped!!
Angle mes BCD = (mes Arc AE-mes ARC BD)/2
Plug: mes BCD = (64+20)/2 = 44° (Number C)