I need help to answer this

What is the greatest common factor of 34, and 85

lisabon 2012 [21]

Answer:

GCF = 17

Step-by-step explanation:

For the values 34, 85

Solution by Factorization:

The factors of 34 are: 1, 2, 17, 34

The factors of 85 are: 1, 5, 17, 85

Then the greatest common factor is 17.

7 0

3 years ago

What is the 25th term of this arithmetic sequence? 3, 9, 15, 21, 27, …

irga5000 [103]

An = a1 + (n - 1)(d)
a1 = the first term in the sequence
d = common difference
n = term
a25 = 3 + (25 - 1)(6)
a25 = 3 + (24)(6)
a25 = 3 + 144
a25 = 147

8 0

4 years ago

Read 2 more answers

Vector d is shown on a centimetre grid. Image attached.

nexus9112 [7]

Answer:

see explanation

Step-by-step explanation:

A column vector has the form $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$

Following the direction of the arrow , the x- displacement = - 3 and y- displacement = 2 , then column vector is

$\left[\begin{array}{ccc}-3\\2\\\end{array}\right]$

h + k

= $\left[\begin{array}{ccc}4\\-3\\\end{array}\right]$ + $\left[\begin{array}{ccc}-2\\-1\\\end{array}\right]$ ← add corresponding elements from each vector

= $\left[\begin{array}{ccc}4-2\\-3-1\\\end{array}\right]$

= $\left[\begin{array}{ccc}2\\-4\\\end{array}\right]$

3 0

3 years ago

Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students

12345 [234]

In general, the height of a projectile is given by

 $h= -\frac 1 2 g t^2 + v t + h_0$

where $h$ is the height at time $t$ of a projectile shot upward at velocity $v$ from initial height $h_0$ .

The acceleration of gravity $g= 9.8 \textrm {m/s}^2 \textrm{ or } g=32\textrm{ feet/s}^2.$ We give it a negative sign in the equation because it pulls down.

Let's apply it to each group.

Group A launches a tennis ball straight up with an initial velocity of 19 meters per second.

We have MKS units, positive (upward) velocity and an initial height of 0.

 $h= -\frac 1 2(9.8) t^2 + (19) t + 0 = -4.9t^2 + 19t$

Group B launches a tennis ball straight up with an initial velocity of 50 feet per second. Not metric, velocity +50, initial height zero.

 $h= -16t^2 + 50t$

Group C drops a tennis ball from a height of 19 meters.

MKS, initial height 19, initial velocity zero.

 $h= -\frac 1 2 g t^2 + v t + h_0 = -4.9 t^2 + 19$

Group D drops a tennis ball from a height of 50 feet.

 $h= -16 t^2 + 50$

6 0

4 years ago

Read 2 more answers

Use the scale factor to compare the perimeter and area of the original figure of the enlarged figure. Complete the statements ab

Reika [66]

Answer:

Part 1) The scale factor is 2

Part 2) The perimeter of the enlarged rectangle is 19 units

Part 3) The area of the enlarged rectangle is 19.5 square units (the area of the enlarged rectangle is 4 times the area of the original rectangle)

Step-by-step explanation:

we know that

A dilation is a non-rigid transformation that produce similar figures