26.2 miles using a fraction is 131/5
Statements are all TRUE
sinA =
and cosB = 
cscA = 1/sinA = 1/(a/c) =
and secB = 1/cosB = 1/(a/c) = 
tanA =
and cotB= 1/tanB = 1/ (b/a) = 
If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:

Referring to a standard normal distribution table, and using z = 0.66, we find:

Therefore

The answer is: 0.2546
just subtracting by 2x on both sides
hope this helps
And where is the graph? I'll change my answer.