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Alexandra [31]
3 years ago
12

Sighient Store

Mathematics
1 answer:
mojhsa [17]3 years ago
5 0
Huh??! The steps are you kidding me??
You might be interested in
Factor completely. x2−2x−24 Enter your answer in the box.
ankoles [38]

Answer:

x = -4

x = 6

Step-by-step explanation:

x² - 2x -24 = 0

x² - 6x + 4x - 24 = 0

x ( x - 6 ) + 4 ( x - 6) = 0

x + 4 and x- 6

so either of them is zero so values if x are

X = -4

X = 6

7 0
3 years ago
Questions in the picture
IrinaVladis [17]

By constructing and solving the <em>profit</em> equation for the <em>cuckoo clock</em> sales, we conclude that the sales of 30 clock will make a profit of $ 4250

<h3>How to determine the monthly profit by the cuckoo clock sales</h3>

The profit (P) is the result of subtracting costs from sales (S). Cost (Cp) is the sum of rent (C) and <em>production</em> cost (C'). Now we proceed to create and solve the expression:

P = S - C - C'

P = 500 · x - 275 · x - 2500

P = 225 · x - 2500

P = 225 · 30 - 2500

P = 4250

By constructing and solving the <em>profit</em> equation for the <em>cuckoo clock</em> sales, we conclude that the sales of 30 clock will make a profit of $ 4250.

To learn more on profits: brainly.com/question/13716014

#SPJ1

6 0
2 years ago
Which statements are true about the ordered pair (7, 19) and the system of equations? {2x−y=−5x+3y=22 Select each correct answer
IRISSAK [1]
(7,19) is a solution for only the first equation (2x-y= -5), so it is not a solution to the system.
2x-y=-5 we substitute the x and y for 7, and 19 making the equation 2 x 7-19, 2 x 7 is 14 so we then put the 14 and 19 together, 14-19, and 14-19 is equal to -5 so the first equation is true. For the second equation which is x+3y=22 we do the same thing as the first equation, we substitute x and y for 7, and 19, substituting these numbers in we get 7+3 x 19, 3 x 19 is 57, so 7+57, which equals 64 and is no where near 22. So, the ordered pair (7,19) is a solution to the first equation because, it makes the first equation true, and the ordered pair (7,19) is not a solution to the system because, it makes at least one of the equations false.


7 0
3 years ago
Read 2 more answers
A company is studying the number of monthly absences among its 125 employees. The following probability distribution shows the l
Angelina_Jolie [31]

Answer:

(1)

E(x) = 0.72

Var(x) = 1.1616

\sigma = 1.078

(2)

E(x) = 12

Var(x) = 1.3

\sigma = 1.14

Step-by-step explanation:

Solving (1):

\begin{array}{ccccccc}{Days} & {0} & {1} & {2} & {3} & {4}& {5} \ \\ {Probability} & {0.60} & {0.20} & {0.12} & {0.04} & {0.04} & {0.00} \ \end{array}

(a): Mean

This is calculated as:

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * 0.60 + 1 * 0.20 + 2 * 0.12 + 3 * 0.04 + 4 * 0.04 + 5 * 0.00

E(x) = 0.72

Solving (b): The variance

This is calculated as:

Var(x) = E(x^2) - (E(x))^2

Where:

E(x) = 0.72

and E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * 0.60 + 1^2 * 0.20 + 2^2 * 0.12 + 3^2 * 0.04 + 4^2 * 0.04 + 5^2 * 0.00

E(x^2) = 1.68

So, we have:

Var(x) = E(x^2) - (E(x))^2

Var(x) = 1.68 - 0.72^2

Var(x) = 1.1616

Solving (c): The standard deviation.

This is calculated as:

\sigma = \sqrt{Var(x)}

\sigma = \sqrt{1.1616}

\sigma = 1.078

Solving (2):

\begin{array}{ccccccc}{x} & {10} & {11} & {12} & {13} & {14}& { } \ \\ {P(x)} & {0.1} & {0.25} & {0.3} & {0.25} & {0.1} & { } \ \end{array}

(a): Mean

This is calculated as:

E(x) = \sum x * P(x)

So, we have:

E(x) = 10 * 0.10 + 11 * 0.25 + 12 * 0.3 + 13 * 0.25 + 14 * 0.1

E(x) = 12

Solving (b): The variance

This is calculated as:

Var(x) = E(x^2) - (E(x))^2

Where:

E(x) = 12

and E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 10^2 * 0.10 + 11^2 * 0.25 + 12^2 * 0.3 + 13^2 * 0.25 + 14^2 * 0.1

E(x^2) = 145.3

So, we have:

Var(x) = E(x^2) - (E(x))^2

Var(x) = 145.3 - 12^2

Var(x) = 1.3

Solving (c): The standard deviation.

This is calculated as:

\sigma = \sqrt{Var(x)}

\sigma = \sqrt{1.3}

\sigma = 1.14

8 0
3 years ago
In a swimming race the winner swam 4 laps in 2 minutes and 8 seconds. What is the average time per lap?
olga nikolaevna [1]
La reponse est 32 seconds
8 0
3 years ago
Read 2 more answers
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