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WITCHER [35]
3 years ago
8

Compare the following fractions 9/10=19/20

Mathematics
2 answers:
Arlecino [84]3 years ago
6 0

Answer:

9/10 < 19/20

Step-by-step explanation:

9/10 and 19/20

2*9/2*10 and 19/20

18/20 < 19/20, so

9/10 < 19/20

Airida [17]3 years ago
4 0

Answer:

9/10 < 19/20

Step-by-step explanation:

I got it right on the test

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What's 29.4983 rounded to the nearest cent
konstantin123 [22]
We need to identify what "the nearest cent" is. 

So! 
AB.CD

That is a representation of a number using variables, but we'll just say it's for place values. 

A is in the Tens Place
B is in the Ones Place
C is in the Tenths Place (1/10)
D is in the Hundredths Place (1/100

Since we are talking about money let's put it in relation to a dollar. 

A is in the Ten Dollar Place
B is in the One Dollar Place
C is in the Tenth of a Dollar Place (1/10 of a dollar)
D is in the Hundredth of a Dollar Place (1/100 of a dollar)

So, what is 1/10 of a dollar? 
What amount of money times 10, would get you 1 dollar. Or you can think of it as if you had 10 of one value of money and you got a dollar what is that? A dime. 

Now, what is 1/100 of a dollar? 
What amount of money times 100, would get you 1 dollar. 1 cent (Or it is sometimes called a penny). 

So that means any number beyond the 1/100 of a dollar point (D) will be rounded. If it's the first number after the 1/100 of a dollar is greater than (or equal to) 5 then we round the cent value up. If it is less than 5 we round down. 

$29.4983
So, 9 is our cent place. 8 is greater than 5, so we round 9 up. (Add 1. Since it is 9 it will carry over into the 1/10 of a dollar place)

Our answer is: 
$29.50

8 0
3 years ago
C=2πr<br> Solve for r<br><br> R=2π/C<br> R=C/2π<br> R=2C/π<br> R=π/2C
Evgen [1.6K]
I hope this helps you


2pi.r=C


r=C/2pi
7 0
3 years ago
The run is the blank
scoray [572]

Answer:

rise over run

Step-by-step explanation:

5 0
3 years ago
a square dance set requires 4 couples 8 dancers with each couple standing on one side of a square. There are 250 people at a squ
sveta [45]

Given:

1 set requires 4 couples 8 dancers.

Total number of people at a square dance = 250.

To find:

The greatest number of sets possible at the dance.

Solution:

We have,

Total people = 250

1 set = 8 people.

\text{Number of possible sets}=\dfrac{\text{Total people}}{\text{People required for 1 set}}

\text{Number of possible sets}=\dfrac{250}{8}

\text{Number of possible sets}=31.25

Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

\text{Number of possible sets}\approx 31

Therefore, the number of possible sets at the dance is 31.

7 0
2 years ago
Giving brainliest to first correct answer:PPP
tia_tia [17]
The correct answer is 317
5 0
2 years ago
Read 2 more answers
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