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GalinKa [24]
3 years ago
10

Solve the equation: 2m-8=34 plz help

Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0

Answer:

m=21

Step-by-step explanation:

valina [46]3 years ago
4 0
M=21 add 8 to both sides simplify divide both sides simplify
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Determine whether 8x + 18 + x is equivalent to 9(2+x) Complete the sentence to justify your answer
AlekseyPX

Answer:

Yes they are equivalent

Step-by-step explanation:

8x + 18 + x = 9x + 18

9(2+x) = 18 + 9x = 9x + 18

Therefore, 8x + 18 + x is equivalent to 9(2+x)

6 0
3 years ago
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The length of each side of a square is 3 inches more than the length of each side of a smaller square the sum of the areas of th
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The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 149 in. $^{2} .$ Find the lengths of the sides of the two squares.
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3 years ago
Which represents the solution(s) of the equation x2 = 49?
Lady_Fox [76]

Answer: 7,-7

Step-by-step explanation: 7 squared is 7 times 7 which equals 49

-7 times -7 is also 49 bc the negatives cancel each other out

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3 years ago
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A tower made of wooden blocks measures​114 feet high. Then a block is added that increases the height of the tower by 8 inches.
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It may be 114ft’ 8” or 1376 or 114.7
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8 0
2 years ago
The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b
storchak [24]

Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so \mu = 145, \sigma = 25.

The fastest 10% are to be given advanced training. What task times qualify individuals for such training?

This is the value of X when Z has a pvalue of 0.90.

Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when Z = 1.285.

So

Z = \frac{X - \mu}{\sigma}

1.285 = \frac{X - 145}{25}

X - 145 = 32.125

X = 177.125

A task time of 177.125s qualify individuals for such training.

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3 years ago
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