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oksano4ka [1.4K]
1 year ago
6

Write the correct function represented in the table below HELP ASAP

Mathematics
1 answer:
Gekata [30.6K]1 year ago
4 0

Answer:

Step-by-step explanation:

y=X-2

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On a cold winter morning, the temperature was -4 degrees C. By noon, the temperature was 0 degrees. Did the temperature increase
solmaris [256]

Answer:

It increased by 4 degrees. It from -4 up to 0.

Step-by-step explanation:

7 0
3 years ago
Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 117 mg/dl and
TiliK225 [7]

Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 117, \sigma = 10.6, n = 6, s = \frac{10.6}{\sqrt{6}} = 4.33

What is the level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L ?

This is the value of X when Z has a pvalue of 1-0.01 = 0.99. So X when Z = 2.33.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

2.33 = \frac{X - 117}{4.33}

X - 117 = 2.33*4.33

X = 127.1

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

6 0
3 years ago
What equation is graphed in this figure?
Ksivusya [100]

to get the equation of any straight line, we simply need two points off of it, let's use those two points in the picture below.

(\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}}\implies \cfrac{3}{1}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_2=m(x-x_2) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_2}{5}=\stackrel{m}{3}(x-\stackrel{x_2}{1})

keeping in mind that for the point-slope form, either point will do, in this case we used the second one, but the first one would have worked just the same.

7 0
2 years ago
You earn $42 for washing 6 cars. How much do you earn for washing 3 cars? Find the unit rate.
antoniya [11.8K]

Answer:

21$

Step-by-step explanation:

42÷6=7

7×3=21

6 0
3 years ago
Read 2 more answers
If I plan to run 400 yards and I have completed 80%, how many yards do I have left?
Dimas [21]

Answer:

You have 80 yards left to run.

Step-by-step explanation:

To solve this problem, we first must realize that if you have completed 80% of the run, that you have 20% left (this is because 100%-80% = 20%).  

Next, we must find 20% of 400 yards.  We must remember that in math, the word "of" represents multiplication.  We also know that 20% = 20/100 = 0.2.

To find 20% of 400 yards, we can perform the following operation:

20% * 400

0.2 * 400

80

Therefore, you have 80 yards left.

Hope this helps!

7 0
3 years ago
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