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3 years ago

12×(3 + 2²)÷2-10= ??????????

Mathematics

2 answers:

aleksklad [387]3 years ago

7 0

12×(3+4)÷2-10

12×7÷2-10

42-10

TEA [102]3 years ago

3 0

Answer:

Step-by-step explanation:

First, do 3+2 to the power of 2 ( which is 3+4 )

Next, Do 12 x 7 ( 84 )

Then divide by 2 ( 84 ÷ 2 = 42 )

Last subtract by 10 to get your answer of 32

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HelpppPppppp me if u do ill give u a pringle

andreev551 [17]

Answer:

D) 2x+10=40, x= 15 rides

Step-by-step explanation:

Since Paul only bought one ticket, then $10 is the constant of the equation. Since Paul pays $2 per ride, $2 will be the rate/coefficient of the equation.

Since we are solving for x, $40 will be on the right side of the equation

Putting these three facts together, we can make the equation 2x+10=40 which means D is correct

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2 years ago

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3 years ago

Which expression represents 75 divided by an unknown number? A. 75 – r B. 75 · r C. 75 ÷ r D. 75 + r

Harman [31]

1. c 2. d and 3,a hope i helped

7 0

3 years ago

Read 2 more answers

Find the area of a triangle bounded by the y-axis, the line f(x)=9−4/7x, and the line perpendicular to f(x) that passes through

Setler79 [48]

<u>ANSWER: </u>

The area of the triangle bounded by the y-axis is $\frac{7938}{4225} \sqrt{65} \text { unit }^{2}$

<u>SOLUTION:</u>

Given, $f(x)=9-\frac{-4}{7} x$

Consider f(x) = y. Hence we get

$f(x)=9-\frac{-4}{7} x$ --- eqn 1

$y=9-\frac{4}{7} x$

On rewriting the terms we get

4x + 7y – 63 = 0

As the triangle is bounded by two perpendicular lines, it is an right angle triangle with y-axis as hypotenuse.

Area of right angle triangle = $\frac{1}{ab}$ where a, b are lengths of sides other than hypotenuse.

So, we need find length of f(x) and its perpendicular line.

First let us find perpendicular line equation.

Slope of f(x) = $\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-4}{7}$

So, slope of perpendicular line = $\frac{-1}{\text {slope of } f(x)}=\frac{7}{4}$

Perpendicular line is passing through origin(0,0).So by using point slope formula,

$y-y_{1}=m\left(x-x_{1}\right)$

Where m is the slope and $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)$

$y-0=\frac{7}{4}(x-0)$

$y=\frac{7}{4} x$ --- eqn 2

4y = 7x

7x – 4y = 0

now, let us find the vertices of triangle, one of them is origin, second one is point of intersection of y-axis and f(x)

for points on y-axis x will be zero, to get y value, put x =0 int f(x)

0 + 7y – 63 = 0

7y = 63

y = 9

Hence, the point of intersection is (0, 9)

Third vertex is point of intersection of f(x) and its perpendicular line.

So, solve (1) and (2)

$\begin{array}{l}{9-\frac{4}{7} x=\frac{7}{4} x} \\\\ {9 \times 4-\frac{4 \times 4}{7} x=7 x} \\\\ {36 \times 7-16 x=7 \times 7 x} \\\\ {252-16 x=49 x} \\\\ {49 x+16 x=252} \\\\ {65 x=252} \\\\ {x=\frac{252}{65}}\end{array}$

Put x value in (2)

$\begin{array}{l}{y=\frac{7}{4} \times \frac{252}{65}} \\\\ {y=\frac{441}{65}}\end{array}$

So, the point of intersection is $\left(\frac{252}{65}, \frac{441}{65}\right)$

Length of f(x) is distance between $\left(\frac{252}{65}, \frac{441}{65}\right)$ and (0,9)

$\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(9-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+0} \\ &=\frac{252}{65} \end{aligned}$

Now, length of perpendicular of f(x) is distance between $\left(\frac{252}{65}, \frac{441}{65}\right) \text { and }(0,0)$

$\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(0-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+\left(\frac{441}{65}\right)^{2}} \\ &=\frac{\sqrt{(12 \times 21)^{2}+(21 \times 21)^{2}}}{65} \\ &=\frac{63}{65} \sqrt{65} \end{aligned}$

Now, area of right angle triangle = $\frac{1}{2} \times \frac{252}{65} \times \frac{63}{65} \sqrt{65}$

$=\frac{7938}{4225} \sqrt{65} \text { unit }^{2}$

Hence, the area of the triangle is $\frac{7938}{4225} \sqrt{65} \text { unit }^{2}$

8 0

3 years ago

A ride on the roller coaster costs 4 tickets while the boat ride only costs 3 tickets. Michael went on the two rides a total of

True [87]

Let x = roller coaster ticket
let y = boat ride ticket

x + y = 10
4x + 3y = 37

x = 10 - y
4x + 3y = 37
4(10-y) + 3y = 37
40 - 4y + 3y = 37
-y = 37 - 40
-y = -3
y = -3/-1
y = 3

x = 10 - y
x = 10 - 3
x = 7

x = 7 ; y = 3

4x + 3y = 37
4(7) + 3(3) = 37
28 + 9 = 37
37 = 37

6 0

3 years ago

12×(3 + 2²)÷2-10= ??????????​

12×(3 + 2²)÷2-10= ??????????