4/9 + 1/3 = ??<br><br> Simplify answer fully

I need help with this last question.

blondinia [14]

Answer:

Step-by-step explanation:

length=1 m

base of triangle=10 m

height=5m

volume= 1/2×10×5×1=25 m cube.

slant height l=√(5²+5²)=√50=5√2

slant surface area=2[5√2×1]=10√2

area of front and back=2×1/2(10×5)=50

total surface area=50+10√2≈50+14.14≈64.14 m²

8 0

3 years ago

Is -12/6 a rational number?

stiv31 [10]

A rational number is any number that can be turned into a fraction....it can be negative or positive.

Therefore, -12/6 is a rational number

3 0

3 years ago

Rachel earned $42 for 3 1/2 hours at her job today. How much does Rachel earn per hour?

Firdavs [7]

The answer is $12 an hour because 12 times 3 is 36 and half of 12 is 6 so add 6 to 36 and you get 42.

8 0

3 years ago

The fan cost index represents the cost of four average price tickets

777dan777 [17]

9514 1404 393

Answer:

soccer: $50.31
hockey: $57.78

Step-by-step explanation:

Let s represent the FCI for soccer. The given values tell us ...

s + (s +7.47) = 108.09

2s = 100.62 . . . . . . . . . . subtract 7.47

s = 50.31

s+7.47 = 57.78

The FCI for soccer was $50.31; the FCI for hockey was $57.78.

8 0

2 years ago

Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar

Mamont248 [21]

Answer:

a

The 95% confidence interval is

$0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

b

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

c

$n = 125 \ stores$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The number of stores that had more than 2 items price incorrectly is k = 52

Generally the sample proportion is mathematically represented as

$\^ p = \frac{ k }{ n }$

=> $\^ p = \frac{ 52 }{ 60 }$

=> $\^ p = 0.867$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{ 0.867 (1- 0.867)}{60} }$

=> $E = 0.0859$

Generally 95% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.867 - 0.0859 < p < 0.867 + 0.0859$

=> $0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

Considering question b

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

Considering question c

From the question we are told that

The margin of error is E = 0.05

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n= [\frac{1.645 }}{0.05} ]^2 * 0.867 (1 - 0.867 )$

=> $n = 125 \ stores$

4 0

3 years ago

4/9 + 1/3 = ?? Simplify answer fully