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likoan [24]
3 years ago
11

Joe has just moved to a smallJoe has just moved to a small town with only one golf​ course, the Northlands Golf Club. His invers

e demand function is
p = 120 - 2 q,
where q is the number of rounds of golf that he plays per year. The manager of the Northlands Club negotiated separately with each person who joins the club and can therefore charge individual prices. This manager has a good idea of what​ Joe's demand curve is and offers Joe a special​ deal, where Joe pays an annual membership fee and can play as many rounds as he wants at ​$​, which is the marginal cost his round imposes on the Club. What membership fee would maximize profit for the Club? The manager could have charged Joe a single price per round. How much extra profit does the Club earn by using two-part pricing?
Business
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

you did not give the value for price. but here is the complete question

Joe has just moved to a smallJoe has just moved to a small town with only one golf​ course, the Northlands Golf Club. His inverse demand function is

p = 120 - 2 q,

where q is the number of rounds of golf that he plays per year. The manager of the Northlands Club negotiated separately with each person who joins the club and can therefore charge individual prices. This manager has a good idea of what​ Joe's demand curve is and offers Joe a special​ deal, where Joe pays an annual membership fee and can play as many rounds as he wants at ​$20​, which is the marginal cost his round imposes on the Club. What membership fee would maximize profit for the Club? The manager could have charged Joe a single price per round. How much extra profit does the Club earn by using two-part pricing?

Answer:

membership fee = $2500

extra profit using 2 part pricing = $1250

Explanation:

p = 120 - 2q

and price, p = 20 dollars = mc

20 = 120 - 2q

20-120 = -2q

-100 = -2q

q = 50

this is the quantity

total supply=\frac{1}{2} (intercept - marginal cost)*quantity\\= 0.5(120-20)50\\= 0.5*100*50\\= $2500

So the maximum membership fee is $2500

TR = PQ

= (120-2Q)Q

= 120-2Q²

we differentiate the above with respect to Q

MR = 120 - 4Q

MC = MR

20 = 120-4Q

20-120 = -4Q

-100 = -4Q

Q = 25

Remember

p = 120 - 2q

= 120 - 2x25

= 120-50

= 70

if single price is charged

(p-MC) x Q

= (70 - 20)x25

= 50 x 25

= $1250

by 2 par pricing, increase in profit would be

= $2500 - $1250

= $1250

thank you!

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