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2 years ago

I needddddddddd helppppppppp

Mathematics

1 answer:

Anika [276]2 years ago

5 0

Answer:

$\frac{2}{-3}$

Step-by-step explanation:

To find the slope you only need two points from the table, and the equation $\frac{y1-y2}{x1-x2}$

(1,-2) (4,-4)

$\frac{-2+4}{1-4}$ = $\frac{2}{-3}$

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A bag has sixteen marbles in it. There are four of each color. There

Ne4ueva [31]

Answer: 25 percent

Step-by-step explanation:

4 0

2 years ago

A survey showed that 77% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 22 adults are

Sveta_85 [38]

Answer:

The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

Step-by-step explanation:

A survey showed that 77% of adults need correction for their eyesight.

If 22 adults are randomly selected, find the probability that no more than more than 11 of them need correction for their eyesight.

n =22

p = 0.77

q = 1-p = 1- 0.77=0.23

We are supposed to find $P(x\leq 11)$

$P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)$

Formula : $P(x=r)=^nC_r p^r q^{n-r}$

$P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}$

Using calculator

$P(x\leq 11)=0.00512$

So, The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

3 0

2 years ago

How do i convert 6 cm cubed to meters cubed??

Svet_ta [14]

6cm^3 =
6* 0.001dm^3=
6*10^(-3)dm^3=
6*10^(-3)*10^(-3)m^3=
6*10^(-6)m^3

or 0.000006 meters cubed

4 0

2 years ago

Which expression shows the result of applying the distributive property to 12(5y+4) ?

yan [13]

The answer would be 60y+48

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2 years ago

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hellohello, this needs to be turned in tomorrow so if you could help, i would really appreciate it. :]

kvv77 [185]

Answer:

Your area is 60in^2 :)

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2 years ago

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