-3x-2-6x=-4-<em>(-4x)</em>+12
-9x-2=-16x+12
7x=14
x=2.
You probably got confused with the italicized part.
Answer:
f(x) = -2x+5
f(x+h) = -2x -2h +5
g(x) = -4x-2
g(x+h) = -4x -4h -2
h(x) = 4x^2+1
h(x+h) = 4(x+h)^2 +1 = 4x^2 +8xh + 4h^2 +1
Q(x) = -3x^2 +4
Q(x+h) = -3(x+h)^2 +4 = -3x^2 -3h^2 -6xh + 4
Answer:

Step-by-step explanation:
We want to solve
, where
.
We rewrite in terms of sine and cosine.


Use the Pythagorean identity:
.




This is a quadratic equation in
.
By the quadratic formula, we have:




or 
or 
or 
When
, 
on the interval
.
When
,
is not defined because 
If Jimmy's new cell cost him $49.99 with a 75% discount, then $49.99 is <span>100%−75%=25%</span><span> of the original price.
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The original price of the cell phone was <span>$199.96</span><span>.</span>
he must buy 24 jackets to get atheist 260 dollars