Find the 11th term of the geometric sequence 10, 20, 40, ...

Solve for each variable and tell how you found the value of each.

AleksAgata [21]

Answer:

A:38 c:54

Step-by-step explanation:

First off, I did the easiest which was a. i found the value of A by subtracting 180 by 142. because a flat line is 180 degrees.

For C, It was more difficult. I subtracted 88 by the value of A, since the value of A is the same as the one next to 88. So I subtracted 126 (88+38) and got 54.

Fortunately, I couldn't figure out B though, but i think it is a similar answer to c.

6 0

3 years ago

1. Stop guys I need help! <br> 3 1/2 -2 1/2

ladessa [460]

Step-by-step explanation:

3 1/2 = 7 /2

2 1/2 = 5 /2

7/2 - 5/2

= 2/2 = 1

hope it helpful

6 0

3 years ago

Derick solves the problem below.

Gala2k [10]

As it is proved that the equation has no solution, Derick is correct

Step-by-step explanation:

Given

$-3(4n + 2) = -4n + -2 (4n - 6)$

We have to solve the equation in order to check if Derick was solved the equation correctly or not.

So,

Applying distributive property first

$-12n -6 = -4n -8n +12\\-12n-6 = -12n+12\\-12n+12n-6 = 12\\-6 = 12$

As the variable is already cancelled in the equation there is no unique solution.

In order for an equation to have infinite solutions the constant on both sides of equation should be same which is not the case in the given equation

So,

As it is proved that the equation has no solution, Derick is correct

Keywords: Linear equations, variables

Learn more about linear equations at:

#LearnwithBrainly

3 0

3 years ago

John, Joe, and James go fishing. At the end of the day, John comes to collect his third of the fish. However, there is one too m

Dmitry [639]

Answer:

The minimum possible initial amount of fish: $52$

Step-by-step explanation:

Let's start by saying that

$x$ = is the initial number of fishes

John:

When John arrives:

he throws away one fish from the bunch

$x-1$

divides the remaining fish into three.

$\dfrac{x-1}{3} + \dfrac{x-1}{3} + \dfrac{x-1}{3}$

takes a third for himself.

$\dfrac{x-1}{3} + \dfrac{x-1}{3}$

the remaining fish are expressed by the above expression. Let's call it John

$\text{John}=\dfrac{x-1}{3} + \dfrac{x-1}{3}$

and simplify it!

$\text{John}=\dfrac{2x}{3} - \dfrac{2}{3}$

When Joe arrives:

he throws away one fish from the remaining bunch

$\text{John} -1$

divides the remaining fish into three

$\dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3}$

takes a third for himself.

$\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}$

the remaining fish are expressed by the above expression. Let's call it Joe

$\text{Joe}=\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}$

and simiplify it

$\text{Joe}=\dfrac{2}{3}(\text{John}-1)$

since we've already expressed John in terms of x, we express the above expression in terms of x as well.

$\text{Joe}=\dfrac{2}{3}\left(\dfrac{2x}{3} - \dfrac{2}{3}-1\right)$

$\text{Joe}=\dfrac{4x}{9} - \dfrac{10}{9}$

When James arrives:

We're gonna do this one quickly, since its the same process all over again

$\text{James}=\dfrac{\text{Joe} -1}{3}+ \dfrac{\text{Joe} -1}{3}$

$\text{James}=\dfrac{2}{3}\left(\dfrac{4x}{9} - \dfrac{10}{9}-1\right)$

$\text{James}=\dfrac{8x}{27} - \dfrac{38}{27}$

This is the last remaining pile of fish.

We know that no fish was divided, so the remaining number cannot be a decimal number. <u>We also know that this last pile was a multiple of 3 before a third was taken away by James</u>.

Whatever the last remaining pile was (let's say $n$ ), a third is taken away by James. the remaining bunch would be $\frac{n}{3}+\frac{n}{3}$

hence we've expressed the last pile in terms of n as well. Since the above 'James' equation and this 'n' equation represent the same thing, we can equate them:

$\dfrac{n}{3}+\dfrac{n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}$

$\dfrac{2n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}$

L.H.S must be a Whole Number value and this can be found through trial and error. (Just check at which value of n does 2n/3 give a non-decimal value) (We've also established from before that n is a multiple a of 3, so only use values that are in the table of 3, e.g 3,6,9,12,..

at n = 21, we'll see that 2n/3 is a whole number = 14. (and since this is the value of n to give a whole number answer of 2n/3 we can safely say this is the least possible amount remaining in the pile)

$14=\dfrac{8x}{27} - \dfrac{38}{27}$