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Len [333]
4 years ago
10

Solve the inequality. 7 - 2q

Mathematics
1 answer:
masya89 [10]4 years ago
7 0
Am I solving for q? Or am I just figuring out the answer.
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A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit
m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0
3 years ago
3(x + 1) = -2 (x - 1) -4
AlekseyPX

Answer:

x = -1

Step-by-step explanation:

use distribution

3x + 3 = -2x + 2 - 4

simplify

3x + 3 = -2x - 2

combine like terms

3x + 3 = -2x - 2

-3x                -3x

3 = -5x - 2

+2         +2

5 = -5x

/-5     /-5

-1 = x

7 0
4 years ago
Read 2 more answers
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

So, we have to impose

x-7\geq 0 \iff x \geq 7

Squaring both sides, we have

(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0
3 years ago
Please help me find the measure of the arc!
andreev551 [17]

Answer:

umm whats a ark XD

Step-by-step explanation:

5 0
3 years ago
The length of a rectangular board is 10 cm longer than its with. The width of the board is 26cm. The board is cut into 9 equal p
Margaret [11]

Answer: 26 cm × 4 cm or

36 cm × 2.89 cm

Step-by-step explanation:

The diagram of the board is shown in the attached photo

Width of the rectangular board is given as 26 cm

The length of a rectangular board is 10 cm longer than its with. This means that

Length of rectangular board = 26 +10 = 36 cm.

Area of rectangular board = length × width. It becomes

36 × 26 = 936cm^2

The board is cut into 9 equal pieces. This means that the area of each piece would be the area of the board divided by 9. It becomes

936 /9 = 104cm^2

The dimensions of the piece would be

Since area of each piece is 104 cm^2 and the width of the bigger board still corresponds to one side of each piece, the other side of each piece will be 104 /26 = 4 cm

Also, the board could have been cut along the length such that one side of the cut piece corresponds to the length of the original board (36 cm)

and the other side becomes

104 /36 = 2.89 cm

The possible dimensions are

26 cm × 4 cm or

36 cm × 2.89 cm

8 0
3 years ago
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