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sdas [7]
2 years ago
5

√

Mathematics
1 answer:
tatuchka [14]2 years ago
6 0

The additional set of values which could be included in the table is; (10,2).

<h3>Which additional set of values can be included in the table?</h3>

As evident in the task content, it follows that for a 15 unit increase in x, depth, there is a 3 unit increase in y, pressure.

On this note, it follows that with each 5 unit increase in x corresponds to 1 unit increase in y.

And ultimately, at x = 10, y = 2 × 1 = 2.

Read more on proportional relationship;

brainly.com/question/2143065

#SPJ1

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Point A is at (3, -8) and point B is at (7, 3). What is the midpoint of line segment AB?​
allochka39001 [22]

Answer:

(5, -5/2)

Step-by-step explanation:

The midpoint of any line segment is the average of the x- and y-values of the two endpoints.

Therefore, the midpoint of AB is ((3+7)/2, (-8+3)/2)=(10/2, -5/2)=(5, -5/2).

So, the answer is \boxed{(5, -5/2)} and we're done!

5 0
2 years ago
I need help with this please
Helen [10]

So burger king offers 10 chicken nuggets for $1.49

   1 chicken nugget = price for 10 chicken nugget / 10 chicken nugget

                         = $1.49 / 10 = $0.15 per nugget (approximated)

Hope that helps!

8 0
2 years ago
Graph the function defined by the parametric equations x = 2t3 – 3t and y = -2t2 – 1 over the parameter
den301095 [7]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

A graphing calculator does this nicely.

4 0
3 years ago
Question 11 of 40
nasty-shy [4]
I don’t know the answer but I need points sorry
7 0
2 years ago
The given line passes through the points and (-4, -3) and (4, 1).
Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

  (x2 , y2) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

  perpendicular line to this line is -1/m

- The point-slope of the equation is y - y_{1}=m(x - x_{1})

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

 through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

4 0
3 years ago
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