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3 years ago

Can anyone help me? I am having trouble figuring it out.

Mathematics

1 answer:

zimovet [89]3 years ago

3 0

It’s 38.67 because you have to use the formula square root and find the base which is B so you have to do hypotenuse reverse

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HELP PLEASE PEOPLE THANK UUUUU ‘

Komok [63]

<h2>The required "option B) 60°" is correct.</h2>

Step-by-step explanation:

In question figure,

∠ YUV = 40°, ∠ XUY = 105° and ∠WUX = 155°

To find, the value of ∠ VUW = ?

We know that,

The circle having 360°

∴ ∠ VUW + ∠ YUV + ∠ XUY + ∠WUX = 360°

⇒ ∠ VUW + 40° + 105°+ 155° = 360°

⇒ ∠ VUW + 300° = 360°

⇒ ∠ VUW = 360° - 300°

⇒ ∠ VUW = 60°

∴ The value of ∠ VUW = 60°

Hence, the required "option B) 60°" is correct.

3 0

3 years ago

Pls help because I have no clue and I am just a dumb 7th grader

frosja888 [35]

So first you have to simply and evaluate the expression . it becomes x>2. plot the point on 2 using an open circle going to the right .

8 0

3 years ago

Frank left his house at 7 a.m. and drove to the airport at a speed of 50 mph. Lance left his house at 6 a.m. and drove to the sa

kodGreya [7K]

Answer:

Frank arrived at 10:00

Step-by-step explanation:

First, we need to ask ourselves how many times can 50 go into 150?

It is 3 times.

So then we do 7:00 + 3 hours which gets us to

10:00.

4 0

3 years ago

Read 2 more answers

PLEASE HELP! I WILL GIVE BRAINLIEST! **GEOMETRY**

Mkey [24]

Answer:

4. 37.8

5. 391 ft

6. 40

7. False

8. $\frac{MB}{AM} =\frac{NC}{AN}$

Step-by-step explanation:

3 0

3 years ago

What are the values of a such that the average value of f(x) = 1 2x − x 2 on [0, a] is equal to 1?

Alexus [3.1K]

The average value of the given function is $f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}$ .

According to the statement

we have given that the function f(x) and we have to find the average value of that function.

So, For this purpose, we know that the

The given function f(x) is

$f(x) = -x^{2} + 2x +1$

And now integrate this function with the limit 0 to a then

$f_{avg} = \frac{1}{b - a} \int\limits^a_0 {f(x)} \, dx = -x^{2} + 2x +1$

Now integrate this then

$f_{avg} = \frac{1}{a} \int\limits^a_0 {-x^{2} + 2x +1} \, dx$

Then the value becomes according to the integration rules is:

$f_{avg} = \frac{1}{a} \int\limits^a_0 {-\frac{x^{3} }{3} + \frac{2x^{2} }{2} +x} \,$

Now put the limits then answer will become as output is:

$f_{avg} = \frac{1}{a} [ {-\frac{a^{3} }{3} + \frac{2a^{2} }{2} +a} \,]$

Now solve this equation then

$f_{avg} = [ {-\frac{a^{2} }{3} + \frac{2a }{2} +1} \,]$

Now

$f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}$

This is the value which represent the average of the given function in the statement.

So, The average value of the given function is $f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}$ .

Learn more about integration here

brainly.com/question/22008756

#SPJ4

7 0

1 year ago