To prove HL you need to prove that the same leg of both of the triangles are congruent and the hypotenuse, and they must be right triangles.
HL- I'd the hypotenuse an a led if a right triangle are congruent to the hypotenuse and a led if another right triangle, then the triangles are congruent.
For SAS, the two sides and the included angle of one triangle are congruent to two sides and the included angle if anther triangle, then the two triangles are congruent.
So you basically need to prove that a side, angle, and a side are congruent......
I really hope that this made sense.....tell me if not.
- Vertex/General Form: y = a(x - h)^2 + k, with (h,k) as the vertex
- (x + y)^2 = x^2 + 2xy + y^2
- Standard Form: y = ax^2 + bx + c
So before I put the equation into standard form, I'm first going to be putting it into vertex form. Since the vertex appears to be (-1,7), plug that into the vertex form formula:
Next, we need to solve for a. Looking at this graph, another point that is in this line is the y-intercept (0,5). Plug (0,5) into the x and y placeholders and solve for a as such:
Now we know that <u>our vertex form equation is y = -2(x + 1)^2 + 7.</u>
However, we need to convert this into standard form still, and we can do it as such:
Firstly, solve the exponent: 
Next, foil -2(x^2+2x+1): 
Next, combine like terms and <u>your final answer will be: 
</u>
Six i think cause it take each wolf 6 minutes to catch a lamb so it should still be six
The correct answer is A, if you use photomath you can usually find the answers to most algebra problems
A) Vertical angles are congruent: It is true. Vertical angles are called opposite angles, so they are congruent.
B) Angles with measures between 0- 90 degrees are complementary: It is false. Complementary angles are angles that the sum of their value is 90°
C) Straight angles are complementary: it is false. Straight angles are angles which value is 180°.
D) Angles with measure between 90 and 180 degrees are obtuse. This statement is true by definition
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