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lisabon 2012 [21]
3 years ago
7

A math recap workshop is provided to the first year students entering a city college. To evaluate the workshop effectiveness, a

study is conducted as following: 20 students with similar math backgrounds are randomly selected for the study. Of the 20 students, 10 of them are selected to attend the workshop and the other 10 do not attend the workshop. After the workshop has taken place a test is given to all 20 students. What is the appropriate inference test to use in this situation
Mathematics
1 answer:
user100 [1]3 years ago
8 0

Answer:

Independent sample t test

Step-by-step explanation:

The Independent sample t test could be explained as a statistical test carried out in other to establish or examine if significant difference exists between two independent samples. That is the outcome of the samples do not depend on one another. Using the scenario described above, the difference between the same variable is measured for two different groups which is the ideal set up for an independent sample t test. The difference between test score for two independent samples (those who attended the workshop and those who did not) is being compared.

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A circle has a radius of 9 inches. The Radius is multiplied by 2/3 to form a second circle. How is the ratio of the areas relate
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Answer:

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{r_{1} }{r_{2}}) ^{2}

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii.

Step-by-step explanation:

Radius of first circle (r_{1}) = 9 inches

Area of first circle = \pi r_{1} ^{2}

Area of first circle = 9 × 9 × π = 81 π

Now, since the radius is multiplied by 2/3 for from a new circle.

∴ Radius of the second circle = 9 \times \frac{2}{3} = 6\ inches

Area of second circle =  \pi r_{2} ^{2}

Area of second circle = 6 × 6 × π = 36 π

Now,

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81\pi }{36\pi }

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{9}{6}) ^{2} = (\frac{r_{1} }{r_{2}}) ^{2}

∵ (r_{1}) = 9 inches and (r_{2}) = 6 inches

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii. i.e., \frac {radius\ of\ first\ circle)^{2} }{(radius\ of\ second\ circle)^{2} } = \frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)}

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