Look at the first digit after the decimal. That digit (if there is no whole number), is in the tenths place, and will, if there is a greater number, let you know which one is the greatest.
D) 0.6 is your answer, because it is greater than all the other numbers by at least 1.
hope this helps
4.23 quarts, just convert it
Answer:16x-6
Step-by-step explanation:4(4x-1) distributed is 16x-6
![{\large\underline{\sf{Solution-}}}](https://tex.z-dn.net/?f=%20%7B%5Clarge%5Cunderline%7B%5Csf%7BSolution-%7D%7D%7D)
Given function is
![\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4}](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3Ay%20%3D%20%20%5Csqrt%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%20)
We know
Domain of a function is defined as set of those real values of x for which function is well defined.
So, y is defined when
![\rm \longmapsto\: {x}^{2} - 4 \geqslant 0](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%20%7Bx%7D%5E%7B2%7D%20-%204%20%5Cgeqslant%200)
![\rm \longmapsto\: {x}^{2} - {2}^{2} \geqslant 0](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%20%7Bx%7D%5E%7B2%7D%20-%20%20%7B2%7D%5E%7B2%7D%20%20%5Cgeqslant%200)
![\rm \longmapsto\: (x - 2)(x + 2) \geqslant 0](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%20%28x%20-%202%29%28x%20%2B%202%29%20%20%5Cgeqslant%200)
![\rm\implies \:x \leqslant - 2 \: \: or \: \: x \geqslant 2](https://tex.z-dn.net/?f=%5Crm%5Cimplies%20%5C%3Ax%20%5Cleqslant%20%20-%202%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20x%20%5Cgeqslant%202)
![\rm\implies \:x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )](https://tex.z-dn.net/?f=%5Crm%5Cimplies%20%5C%3Ax%20%5C%3A%20%20%5Cin%20%5C%3A%20%28%20-%20%20%5Cinfty%20%2C%20%20%5C%3A%20-%202%5D%20%5C%3A%20%20%5Ccup%20%5C%3A%20%5B2%2C%20%5C%3A%20%20%5Cinfty%20%29)
Now, <u>To find the range of function </u>
We know,
Range of a function is defined as set of those real values which is obtained by assigning the values to x.
So,
![\rm \longmapsto\:y = \sqrt{ {x}^{2} - 4}](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3Ay%20%3D%20%20%5Csqrt%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%20)
On squaring both sides, we get
![\rm \longmapsto\: {y}^{2} = {x}^{2} - 4](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%20%7By%7D%5E%7B2%7D%20%3D%20%20%7Bx%7D%5E%7B2%7D%20-%204)
![\rm \longmapsto\: {y}^{2} + 4= {x}^{2}](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%20%7By%7D%5E%7B2%7D%20%20%2B%204%3D%20%20%7Bx%7D%5E%7B2%7D)
![\rm \longmapsto\:x = \sqrt{ {y}^{2} + 4 }](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3Ax%20%3D%20%20%5Csqrt%7B%20%7By%7D%5E%7B2%7D%20%2B%204%20%7D%20)
Now, x is defined when
![\rm \longmapsto\: {y}^{2} + 4 \geqslant 0 \: which \: is \: always \: true \: \forall \: y \in \: real \: number](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%20%7By%7D%5E%7B2%7D%20%2B%204%20%5Cgeqslant%200%20%5C%3A%20which%20%5C%3A%20is%20%5C%3A%20always%20%5C%3A%20true%20%5C%3A%20%20%5Cforall%20%5C%3A%20y%20%5Cin%20%5C%3A%20real%20%5C%3A%20number)
But,
![\rm \longmapsto\:y \geqslant 0](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3Ay%20%5Cgeqslant%200)
<u>Hence, </u>
![\rm\implies \:Range \: of \: function \: = [0, \: \infty )](https://tex.z-dn.net/?f=%5Crm%5Cimplies%20%5C%3ARange%20%5C%3A%20of%20%5C%3A%20function%20%5C%3A%20%20%3D%20%5B0%2C%20%5C%3A%20%20%5Cinfty%20%29)
So, we have
![\rm\implies \:Domain \: of \: function : x \: \in \: ( - \infty , \: - 2] \: \cup \: [2, \: \infty )](https://tex.z-dn.net/?f=%5Crm%5Cimplies%20%5C%3ADomain%20%5C%3A%20of%20%5C%3A%20function%20%3A%20x%20%5C%3A%20%20%5Cin%20%5C%3A%20%28%20-%20%20%5Cinfty%20%2C%20%20%5C%3A%20-%202%5D%20%5C%3A%20%20%5Ccup%20%5C%3A%20%5B2%2C%20%5C%3A%20%20%5Cinfty%20%29)
and
![\rm\implies \:Range \: of \: function \: = [0, \: \infty )](https://tex.z-dn.net/?f=%5Crm%5Cimplies%20%5C%3ARange%20%5C%3A%20of%20%5C%3A%20function%20%5C%3A%20%20%3D%20%5B0%2C%20%5C%3A%20%20%5Cinfty%20%29)
Answer:
Step-by-step explanation:
The rent will increase 11 times before the 12th year
<u>Required equation:</u>
- $1700*(1 + 0.09)^11 = $4386.70 (rounded)