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lisov135 [29]
3 years ago
13

Can anyone help me please ! Problem shown on the picture

Mathematics
2 answers:
valentina_108 [34]3 years ago
7 0
Correct coordinates of the image are (0,4)
soldier1979 [14.2K]3 years ago
7 0
(0,4) would be the answer
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What is the repulsive force between two pith balls that are 13.0 cm apart and have equal charges of −24.0 nC?
daser333 [38]

Answer:

The repulsive force is 3.067\times10^{-4}N.

Step-by-step explanation:

Consider the provided information.

The coulomb's law to calculate the repulsive force: F=\frac{kQ_1Q_2}{r^2}

Where the value of k is 9.00×10⁹ Nm²/C²

Substitute the respective values in the above formula.

F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{[(13 cm)(\frac{1m}{100cm} )]^2}

F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{(0.13 m)^2}

F\approx0.0003067N

F=3.067\times10^{-4}N

Hence, the repulsive force is 3.067\times10^{-4}N.

8 0
3 years ago
Help please, I really need to get this test passed
ad-work [718]

Answer:

the secound ansewr

Step-by-step explanation:ik

3 0
3 years ago
Which expression is equivalent to 13 - -21
Ber [7]
13 + 21 = 13- -21

The minus sign and negative cancel each other out.
5 0
3 years ago
Round 5.928301 to 2 decimal places
Artist 52 [7]
Look to the 3rd decimal, 8. it rounds up, so the answer is **5.93**
7 0
3 years ago
I need all the answers please asap
olganol [36]

5. they give dimes of 2 identical sides 25 & 5

25/5 = 5 so ABC is 5 times larger so 12 x 5 = 60

6. V= L x W x H/3 = 6.2 x 4.5 x 5.3 = 147.87/3 = 49.29 cubic cm

7 add both losses 3 and a half + 3 and a half = 728 and a half - 7 = 21 and a half


6 0
3 years ago
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