K=4
add seven on both sides
2x-4y=7
add 4y on both sides
2x=7+4y
divide 2 on both sides
x=7+4y/2
plug that into original equation
2(7+4y/2)-4y-7=0
7 and 4y cancel out
2(2)=0
4=0
Given:
Length of rectangle = (x+10) cm
Width of the rectangle = x cm
Perimeter = 32 cm
To find:
The length of the rectangle.
Solution:
We know that,
Where, l is length and w is width.
Substituting the values, we get
Subtract 20 from both sides.
Divide both sides by
So, the length is
Therefore, the length of the rectangle is 13 cm.
Answer:
c
Step-by-step explanation:
1 + tan²theta = sec²theta
tan²theta = 3² - 1
tan²theta = 8
tan theta = sqrt(8)
Positive because Quadrant 1
sqrt(8) = sqrt(4×2) = sqrt(4)×sqrt(2)
= 2×sqrt(2)
nice day folks eeeeeeeeeeeeeeeee
Since it's a wall, I'm guessing it will only have access to half the circle? Therefore:
<em>Circle area formula: </em>πr²
<em>Radius:</em> 12/2 = 6ft
<em>Our case:</em>
(π * 6²)/2 =
36π/2 =
18π = 56.55ft²
