Numerators:
3
7
12
0
Denominators:
2
512
10
78
Answer:
Step-by-step explanation:
Given that every day at noon, a bus leaves for Townville and travels at a speed of x kilometers per hour. Today, the bus left 30 minutes late.
If the driver drives 7/6 times as fast as usual, she will arrive in Townville at the regular time.
If correct time leaves then distance = time *speed
280 = t*x where t is the time in hours
Or t = 280/x
Now speed changes to 7x/6 while time changes to (t-1/2)
So 280 = (t-1/2) 7x/6

x = 80 km per hour
54 can be factored as follows:
54
2*27
2*3*9
2*3^2*3
2*3^3
Therefore, 54 is equal to 2*3^3, or 2*3*3*3.
Three angles measuring 45, 45, 45