If
and
are <span>supplementary angles, then
The ratio of
and
is
<span>
Substitute
into
From
we find the measure of
</span></span>
Answer:
40
Step-by-step explanation:
area of shaded region = area of whole figure - area of non shaded region
area of whole figure: The whole figure is a rectangle
The area of a rectangle can simply be calculated by multiplying the width by the length
The given width is 10ft and the given length is 8ft
Hence area of whole figure = 10 * 8 = 80ft²
Area of non shaded region: the non shaded region also creates a rectangle
Like stated previously the area of a rectangle can simply be calculated by multiplying the width by the length
The given width is 5ft and the given length is 8ft
Hence, area of non shaded region = 5 * 8 = 40ft²
Finally we can find the area of the shaded region.
We can easily do this my subtracting the area of the nonshaded region from the area of the whole figure
If we have identified that the area of the whole figure is 80 and the area of the non shaded region is 40
Then, area of shaded region = 80 - 40 = 40ft²
Answer:
9/100
Step-by-step explanation:
You find 1/8 of 3/4 which is 9/100
Let after n week both tanks have same quantity of water .
for first tank
=============
tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
==============
quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
