Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
x^3-6x^2+18x-2 is right snswer
3,806,000 is the correct answer.
There are three in the millions place and 806 in the thousands. There are no numbers in the hundreds so you place zeros.
What you have to do is add all of the numbers:
5.98 + 16.39 + 2.25 + 2.29 =
$26.91
Hope that helps!
X should equal -13.33. Y is correct, 13.33