All categories

3 years ago

Solve for the missing side. Round to the nearest tenth. HELP MEEE PLS ):

Mathematics

1 answer:

Bingel [31]3 years ago

8 0

Answer:

b² = 13.2

Step-by-step explanation:

5.8²+b²=14.4²

33.64+b²=207.36

-33.64 -33.65

b²= √173.71

b² = 13.1799089526

b² = 13.2

You might be interested in

18+(-4)-2/7j-6/7j+5=

kow [346]

18 - 4 - 2/7j - 6/7j + 5 =
18 - 4 + 5 - 2/7j - 6/7j=
19 - 8/7j

4 0

2 years ago

A circular plate has circumference 32 inches. What is the area of this plate? Use 3.14 for pi. The area of this plate is about

Novosadov [1.4K]

Answer:

A = 82.53 in²

Step-by-step explanation:

We use the circumference equation C = 2πr and the area equation A = πr².

Using the first equation and the given circumference (32 in), we find the radius of the circle, and then use this result to find the area of the circle.

C 32 in

C = 2πr becomes r = ----------- and here r = ---------- = 5.10 in

2π 6.28

Then the area of the circle is A = πr², which here is A = 3.14(5.10 in)², which, when rounded off to two decimal places, is A = 82.53 in²

6 0

3 years ago

Write an expression for number 26 if x is an unknown number

hram777 [196]

1.3 bc 8 miss 3 equals 24

5 0

2 years ago

Read 2 more answers

Addy has 51.79 pounds of dirt. She has buckets in her garage. Each bucket can hold 2.5 pounds of dirt. If she has 20 buckets wil

kirill [66]

Answer:

Step-by-step explanation:

20x2.5=50

51.79-50=1.79

therefore there isn't enough buckets for all the dirt.

4 0

2 years ago

Read 2 more answers

IQ scores are normally distributed with a mean of 100 and a standard deviation of 15.

jekas [21]

Using the normal distribution, it is found that 1851 people would have an IQ less than 115.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 100, \sigma = 15$

The proportion of IQ scores less than 115 is the <u>p-value of Z when X = 115</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{115 - 100}{15}$

Z = 1

Z = 1 has a p-value of 0.8413.

Out of 2200 people:

0.8413 x 2200 = 1851.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

5 0

1 year ago