Find the measure of the angle indicated in bold

Mathematics

1 answer:

Brums [2.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

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A square technology chip has an area of 25 square centimeters how long is each side of the chip

grigory [225]

ANSWER

Each side of the chip is 5 centimeters long.

EXPLANATION

The chip is in the form of a square.

The formula for finding the area of a square is

$Area=l^2$

We were given in the question that, the area is 25 square centimeters. This means that,

$25=l^2$

We take the square root of both sides to get,

$\sqrt{25}=l$

$\Rightarrow 5=l$

Hence the length of the square technology chip is 5 centimeters

5 0

3 years ago

Help please I don't understand!!!

shusha [124]

A- 2b = 2 one of the 2 "A" most be negative so they can cancer each other
-a- b = 6 after the "A" cancel each other add the -2b with -b = -3b, then add 2
-------------- and 6
-3b=8 then you have to divide 8 by -3 = -2.6 -2.6 its b... now you have to solve for b step 1. a -2b = 2 step 2. a -2(-2.6)=2 step 3 a -5.3 = 2 then subtract -5.3 with 2 so that going to be 2 + 5.3 =7.3 then divide by a
final answer (-2.5,-7.3)
sorry its kinda hard to explained here, i hope you get the point :)

3 0

3 years ago

A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)

Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}$