Split up the interval [0, 3] into 3 equally spaced subintervals of length 
. So we have the partition
[0, 1] U [1, 2] U [2, 3]
The left endpoint of the 
-th subinterval is
where 
.
Then the area is given by the definite integral and approximated by the left-hand Riemann sum
<span>x – 12 ≥ 18
Let's break down the sentence and create an inequality from it. We'll use X to represent the number.
"Twelve fewer than a number is at least 18."
The "Twelve fewer than a number" indicates subtraction, so let's do that.
X - 12
"is at least 18." would be a greater than or equal relationship. So we have
X - 12 ≥ 18
And we're done. The desired equation is:
x – 12 ≥ 18</span>
This is easy. You just add all the like terms
Step-by-step explanation:
Statement | Reason
CB=AB Given
DBC=DBA Given
DB = DB Reflexive Property
/_\ DBC
=~
/_\DBA SAS
Sorry for the formatting the =~ means congruent.
Answer:
i dont see a # line..
Step-by-step explanation:
hmm hmm
