None are given. You have to invent your own points that satisfy the given equation.
Examples: If x = 0, y = -5000 => (0,-5000)
If x = 2, y = -(2)^2 + 160(2) - 5000 = 4 + 320 - 5000 => (2, -4676)
and so on. Find as many such points as you want, using the same approach.
Answer:
Part 1) The quadratic equation has zero real solutions
Part 2) The solutions are
and
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
The discriminant is equal to

If D=0 -----> the quadratic equation has only one real solution
If D>0 -----> the quadratic equation has two real solutions
If D<0 -----> the quadratic equation has two complex solutions
<em>Find the value of D</em>
-----> the quadratic equation has two complex solutions
<em>Find out the solutions</em>
substitute the values of a,b and c in the formula
Remember that

. Given that the slope<span> of a </span>line<span> is </span>3<span> and the </span>line passes through<span> the point (-2,</span>4<span>)</span>
15x would be the vertical angle of 16x -8 and since vertical angles are equal, then 15x = 16x -8.
15x = 16x -8
x = 8 and so the angle 15x = 15 * 8
which equals 120 degrees.