Question

Find the equation of the tangent to the curve

Answer 1

9514 1404 393

Answer:

  y = -x/16 +1

Step-by-step explanation:

The slope is at any point x is ...

  y' = -4/x^2

so, at x=8, the slope is ...

  m = -4/8^2 = -4/64 = -1/16

The point-slope form of the equation of the line is ...

  y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

Then the line with slope -1/16 through point (8, 1/2) is ...

  y - 1/2 = -1/16(x -8)

  y = -1/16x +1/2 + 1/2 . . . . . eliminate parentheses, add 1/2

  y = -1/16x +1 . . . . . equation of the tangent line