Answer:
all of them are valid solutions
Step-by-step explanation:
So we plug in values of t below and get:
18 is < 107
54 is < 107
36 is < 107
27 is <107
Answer:
Enlargement.
Scale Factor: 3
Step-by-step explanation:
Use points to find the enlargement. Typically, you will use all the points.
A(1 , 1) ⇒ A'(3 , 3)
B(2 , 1) ⇒ B'(6 , 3)
C(1 , 2) ⇒ C'(3 , 6)
D(2 , 2) ⇒ D'(6 , 6)
To find the scale factor, simply divide the Point' with the original Point. Use any number.
A'(3 , 3)/(A(1 , 1)) = 3
B'(6 , 3)/(B(2 , 1)) = 3
C'(3 , 6)/(C(1 , 2)) = 3
D'(6 , 6)/(D(2 , 2)) = 3
Your scale factor is 3.
~
The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
Adult ticket (a) = $5
Child ticket (c) = $2
785 tickets = $3280
a + c = 785 tickets
5a + 2c = $3280
c = 215 child tickets
a = 570 adult tickets
570 + 215 = 785 tickets
5(570) + 2(215) = $3280
There were 215 child tickets sold on Saturday
The standard for is 2000+ 1200
