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Oxana [17]
2 years ago
14

The area of the poster is (x^2+2x-15) inches the width is (x-3) inches calculate the dimensions of the poster board when x=14

Mathematics
1 answer:
givi [52]2 years ago
4 0

Answer:

The poster is 11 inches wide and 19 inches in height.

Step-by-step explanation:

We take the given equation: (x^2+2x-15) and we add in 14 as our x variable:

((14)^2+2(14)-15) the answer we get from that is 209. The area of the poster is 209 square inches. Then we find the width by taking (x-3) in this case x is 14 so the width of the poster is 11. In order to find the height we divide the height by the width and we get 19.

Therefore:

Height= 19 Inches

Width= 11 Inches

Total Area= 209 Square Inches

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3 0
3 years ago
(1.)Find the slope of the line that passes through the given pair of points. (If an answer is undefined, enter UNDEFINED.) (?a +
jekas [21]

Answer:

1. The slope of the line is m=\frac{-2b+3}{2a}.

2. The value of a is 18.

Step-by-step explanation:

If a line passes through two points, then the slope of the line is

m=\frac{y_2-y_1}{x_2-x_1}

(1)

It is given that the line passes through the points (-a + 3, b - 3) and (a + 3, -b). So, the slope of the line is

m=\frac{-b-(b-3)}{a+3-(-a+3)}

m=\frac{-b-b+3}{a+3+a-3)}

m=\frac{-2b+3}{2a}

The slope of the line is m=\frac{-2b+3}{2a}.

(2)

If the line passing through the points (a, 1) and (6, 5), then the slope of the line is

m_1=\frac{5-1}{6-a}=\frac{4}{6-a}

If the line passing through the points (2, 7) and (a + 2, 1), then the slope of the line is

m_2=\frac{1-7}{a+2-2}=\frac{-6}{a}

The slopes of two parallel lines are same.

m_1=m_2

\frac{4}{6-a}=\frac{-6}{a}

On cross multiplication we get

4a=-6(6-a)

4a=-36+6a

4a-6a=-36

-2a=-36

Divide both sides by -2.

a=18

Therefore the value of a is 18.

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3 years ago
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Answer:

D

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(p² + 3p + 6) + (2p² + 6p + 6)

First you must combine (aka sum) like terms. Like terms are numbers that have matching variables OR are numbers with out variables OR have matching variables with matching exponents. In this case the like terms are p² and 2p² (they both have the exponent p that is squared); 3p and 6p (they both have the variable p attached); and 6 and 6 (both numbers without variables)

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