Answer:
I believe 3
Step-by-step explanation:
The greatest perimiter
let's experiment weather we want to have sides with as close to each other as possible, or with as far apart form each other
so if we have lenth times width, peimiter=legnth+legnth+widht+width
1 times 39:perimiter=80
3 times 13:perimiter=52
so we want one side as small as possible
0.1 times 360:perimiter=720.2
let's see how far we can go
0.00000000000000000001 times 3600000000000000000000=3,600,000,000,000,000,000,000.00000000000000000001
you get the idea
that is a really big perimiter
if you can be that exact
so just make a really small decimal
if you haven't learned decimals yet and only know whole numbers then
80 ft is the greatest perimiter made (with sides of 39,1,39,1)
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
Answer:
so you can simplify the ratio
Step-by-step explanation:
